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ruslelena [56]
2 years ago
9

When is the object at rest? in constant speed? accelerating?​

Physics
1 answer:
12345 [234]2 years ago
6 0

Answer:

Answered in explanaion.

Explanation:

<u>REST</u>: When an object does not change its position with respect to its frame of reference or surrounding, then the object is said to be in the state of rest.

<u>CONSTANT SPEED</u>: When the object covers equal distance in equal intervals of time, the object is said to be moving with constant speed.

<u>ACCELERATING</u>: An object is said to be accelerating when the speed of the object increases with respect to time.

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Which of the following has the most potential energy?
Alex
A Car at the top of a hill.

It is because in that case, produce of mass and height is highest which is directly proportional to potential energy 

In short, Your Answer would be Option A

Hope this helps!
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2 years ago
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Two 13 cm -long thin glass rods uniformly charged to +11nC are placed side by side, 4.0 cm apart. What are the electric field st
DedPeter [7]

Answer:

E1  = 10.15 * 10^4 N/C

E2 = 0

E3 = 10.15 *10^4 N/C

Explanation:

Given data:

Two 13 cm-long thin glass rods ( L ) = 0.13 m

charge (Q)  = +11nC

distance between thin glass rods   = 4 cm .

<u>Calculate the electric field strengths </u>

electric charge due to a single glass rod in the question ( E ) = \frac{Q}{2\pi e_{0}rL }

equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced

applying equation 1 to determine E1

E1 = \frac{Q}{2\pi e_{0}rL } ( \frac{1}{0.01} - \frac{1}{0.03} )    ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )

   = \frac{11*10^{-9} }{2*3.14*8.85*10^{-12}*0.13 } ( 66.67 )

   = 10.15 * 10^4 N/C

applying equation 1 to determine E2

E2 = \frac{Q}{2\pi e_{0}rL }( \frac{1}{0.02} - \frac{1}{0.02} )

therefore E2 = 0

E1 = E3

hence E3 = 10.15*10^4 N/C

4 0
2 years ago
Match the following items.
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How does increasing the distance between charged objects affect the electric force between them? the electric force increases be
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the electric force decreases because the distance has an indirect relationship to the force

Explanation:

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where

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As we can see from the formula, the magnitude of the force is inversely proportional to the square of the distance: so, when the distance between the object increases, the magnitude of the force decreases.

3 0
3 years ago
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3 years ago
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