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storchak [24]
3 years ago
14

Why does of beam of light ben when it passes into a new medium?

Physics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

The bending occurs because light travels more slowly in a denser medium.

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Help please!!!!!!!!!!!!!!!!!!!!
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Looks like you need to review through the lesson and take notes as it tells you in the lesson what each of these are.
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Sam and his Dad went grocery shopping. As they went up and down the aisle, adding items to their cart, something changed. The ca
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The speed of the cart changed because it stopped. 

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Which two pieces of data indicate that Uranus resides in the outer region of the solar system
LuckyWell [14K]

Answer:

Our solar system has total eight planets out of which four are inner planets and four are outer planets. The four outer planets are Jupiter, Saturn, Uranus and Neptune. The common characteristics of outer planets is that they are gaseous planets. They are larger on size than the inner rocky planets and are faraway from Sun. They have larger period of revolution around the Sun.

Uranus is a gaseous planet and lies far from Sun and hence has large period of revolution. It takes 84 Earth years to revolve around Sun. This data indicates that Uranus resides in the outer region of the Solar System.

4 0
3 years ago
El cuerpo de una persona está cubierto con 1.6 m2 de ropa de lana. El grosor de la lana es 2.0 x 10-3 metro. La temperatura en l
netineya [11]

Answer:

<h2>Rate of heat transfer from the body of the person is given as</h2><h2>\frac{dQ}{dt} = 800 J/s</h2>

Explanation:

As we know that the rate of heat transfer due to thermal conduction is given as

\frac{dQ}{dt} = \frac{kA(T_2 - T_1)}{x}

so we have

k = 0.04 W/m C

A = 1.6 m^2

x = 2\times 10^{-3} m

\frac{dQ}{dt} = \frac{(0.04)(1.6)(36 - 11)}{2 \times 10^{-3}}

\frac{dQ}{dt} = 800 J/s

8 0
3 years ago
Astronauts on the first trip to Mars take along a pendulumthat has a period on earth of 1.50 {\rm s}. The period on Mars turns o
svetlana [45]

Answer:

3.7 m/s^2

Explanation:

The period of a simple pendulum is given by:

T=2 \pi \sqrt{\frac{L}{g}}

where L is the length of the pendulum and g is the free-fall acceleration on the planet.

Calling L the length of the pendulum, we know that:

T_e = 2 \pi \sqrt{\frac{L}{g_e}}=1.50 s is the period of the pendulum on Earth, and g_e = 9.8 m/s^2 is the free-fall acceleration on Earth

T_m = 2 \pi \sqrt{\frac{L}{g_m}}=2.45 s is the period of the pendulum on Mars, and g_m = ? is the free-fall acceleration on Mars

Dividing the two expressions we get

\frac{T_e}{T_m}=\sqrt{\frac{g_m}{g_e}}

And re-arranging it we can find the value of the free-fall acceleration on Mars:

g_m = g_e \frac{T_e^2}{T_m^2}=(9.8 m/s^2)\frac{(1.50 s)^2}{(2.45 s)^2}=3.7 m/s^2

4 0
3 years ago
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