When the oil is added to the heated copper, the energy in the system is
conserved.
- The mass of the oil in the cup, is approximately <u>64.73 grams</u>.
Reasons:
The question parameters are;
Temperature of the oil in the cup = 25.00°C
Final temperature of the oil and copper, T₂ = 27.33 °C
Specific heat of copper, c₂ = 0.387 J/(g·°C)
Specific heat capacity of oil, c₁ = 1.74 J/(g·°C)
Required:
The<em> mass of oil</em> in the cup.
Solution:
The mass of the copper, m₂ = 17.920 g
Temperature of copper after heating, T₂ = 65.17°C
Temperature of the copper after being placed in the cup of oil, T₂ = 27.33°C
Heat lost by copper = Heat gained by the oil
- m₂·c₂·(T₂ - T₃) = m₁·c₁·(T₃ - T₁)
Therefore, we get;
17.920 × 0.387 × (65.17 - 27.33) = m₁ × 1.74 × (27.33 - 25)
262.4219136 = 4.0542·m₁
m₁ ≈ 64.73
- The mass of the oil in the cup, m₁ ≈ <u>64.73 g</u>
Learn more here:
brainly.com/question/21406849
<em>Possible part of the question obtained from a similar question online, are;</em>
<em>The mass of the copper, m₂ = 17.920 g</em>
<em>Temperature of copper after heating = 65.17°C</em>
