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3 years ago

What type of reaction is shown in this thermochemical equation? A + B + heat → C + D

Chemistry

2 answers:

Mademuasel [1]3 years ago

5 0

Answer: Option (a) is the correct answer.

Explanation:

A chemical reaction in which there will be absorption of heat energy by the reactant molecules is known as endothermic reaction.

For example, $A + B + Heat \rightarrow C + D$ is an endothermic reaction.

On the other hand, a chemical reaction in which there will be release of heat energy is known as an exothermic reaction.

For example, $A + B \rightarrow C + D + Heat$ is an exothermic reaction.

Therefore, we can conclude that the given thermochemical equation $A + B + Heat \rightarrow C + D$ shows endothermic type of reaction.

hodyreva [135]3 years ago

3 0

The reaction, as what is depicted in the thermonuclear equation is one of the best example of an endothermic reaction. In addition, the endothermic process revolves around the idea that the system can also absorb the energy from its surroundings, in contrast to the idea of releasing its energy to its environment.

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Which system is responsible for carrying oxygen to the muscle

Nitella [24]

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Circulatory system is probably the answer you are looking for.

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3 years ago

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What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?

Solnce55 [7]

We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+ + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:

PH= -㏒[H+]
= -㏒(4.81x10^-7) = 6.32

3 0

3 years ago

A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe

Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: $V_{1}$ = 571 mL, $T_{1} = 26^{o}C$

(a) $T_{2} = 5^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL$

(b) $T_{2} = 95^{o}F$

Convert degree Fahrenheit into degree Cesius as follows.

$(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL$

(c) $T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL$

8 0

3 years ago

Need chem help asap

gavmur [86]

Oh I’m so4+ds2=563

Which is the answer

5 0

3 years ago

1/ Which graph illustrates constant speed and velocity

Maksim231197 [3]

Velocity is said to be constant if its magnitude as well direction at any instant is remains the same. In D, if you draw a line parallel to y-axis at any time t, you can see that velocity is same. Hence, D is the correct graph.

The kinetic energy of gaseous molecules is greater than that of liquid molecules. Therefore, in gas, kinetic energy overcomes the force of attraction between molecules. In short, in gas phase, particles move at high speed and hence they have less force of attraction. In case of liquid phase, particles are close enough as a result there is much more force of attraction compared to gaseous molecules. In liquid state, kinetic energy cannot overcome force of attraction therefore, liquid molecules slow down.

Therefore, B is the correct answer.

4 0

3 years ago