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Travka [436]
2 years ago
15

Sharia surveyed students and teachers to determine how long it takes each person, in minutes, to get ready for school in the mor

ning. The plots below show the results of the survey. Which statements accurately compare the two data sets? Select three options
Mathematics
1 answer:
AysviL [449]2 years ago
8 0

Answer/Step-by-step explanation:

It typically takes teachers 9 minutes longer than students to get ready for school. - The median of two data = Teachers 25 - Students 16: typically, teachers take 25 mins to get ready and students take 16 mins to get ready.

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Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,
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We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

  • \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }  

In order to use t*, we need to check conditions for using a t-distribution first.

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<u>Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.</u>

<u>Solve for t*:</u>

<u></u>

We need the <u>tail area </u>first.

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Next we need the <u>degree of freedom</u>.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

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Use a calculator or a t-table to find the corresponding <u>t-score for df = 5 and tail area = .05</u>.

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Substitute the variables into the formula: \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }.

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Simplify this expression.

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If we want to <u>interpret</u> the confidence interval of (-20.5707, -11.4293), we can say...

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