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Marina86 [1]
3 years ago
5

Please help me I want to be sure I will mark you

Chemistry
2 answers:
defon3 years ago
7 0

Answer:

Probably A.

Explanation:

Its either A or C. A is more probable imo

marissa [1.9K]3 years ago
7 0

Answer:

that's right

Explanation:

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Am I right? Yes or no?
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yes because it is right and because

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Can cornstarch disintegrate in fire or an open flame?
ArbitrLikvidat [17]
In an open flame because it can not only catch on fire extremely easily but also cause an explosive
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3 years ago
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1. Here is a chemical equation: C2H2 + O2 → CO2 + H2O
Evgen [1.6K]

Answer:

1)  a) 2 C2H2 +  3O2 -->  2CO2 +  2H2O

b) Combustion Reaction

c) Bonds will be broken on the reactant side which will require energy.

d) It agrees with the law of conservation of mass because there are the same amount of molecules of each element on both sides of the equation, meaning mass was not created nor destroyed.

2) a) 2Na + Cl2 --> 2NaCl

        Synthesis

   b) 2Fe + O2 --> 2FeO

        Synthesis

Hope this helps!

Explanation:

6 0
2 years ago
Water is wet. true or false? Why?
Vikentia [17]

Answer:

True water is wet because when something is wet in this case it's water it has water on it at a molecular level. Water molecules are bonded on top of each other so it's wet.

5 0
3 years ago
KNO3(s) --> K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r
nataly862011 [7]

Answer:

Equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

Explanation:

Mass of aqueous solution = m = 100 g

Specific heat of solution = c = 4.18 J/gºC

Change in temperature = \Delta T=T_f-T_i

ΔT = 21.6ºC - 30.0ºC = -8.4ºC

Heat lost by the solution = Q

Q = mc\Delta T

Q=100 g\times 4.18 J/g^oC\times (-8.4^oC)

Q = -3,511.2 J ≈ -3.51 kJ

Heat absorbed by potassium nitrate when solution in formed; Q'

Q' = -Q = 3.51 kJ

Moles of potassium nitrate , n= \frac{10.1 g}{101 g/mol}=0.1 mol

KNO_3(s)\rightarrow K^+(aq) + NO_{3}^-(aq)

The heat of solution =

\frac{Q'}{n}=\frac{3.5112 kJ}{0.1 mol}=35.1 kJ/mol

So, the equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

4 0
4 years ago
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