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3 years ago

10

In some companies, workers who increase the quantity or quality of their work receive a. benefits. c. performance bonuses. b. pe

nsion plans. d. orientation. Please select the best answer from the choices provided A B C D

1 answer:

Greeley [361]3 years ago

3 0

Answer:

performance bonuses

Explanation:

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The scale of the blueprint tells us the<br> of drawing to real space?

klasskru [66]

Answer:

yes

Explanation:

blueprint of the construction is a prediction of project its is slightly auto cad

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3 years ago

An electronic toy is powered by three 1.58-V alkaline cells, each with an internal resistance of 0.0205 Ω, and a 1.53-V carbon-z

mina [271]

Answer:

(a) The current in amperes that flows through the toy's circuit is 0.923A

(b) The power supplied to the toy is 5.78721W

(c) The internal resistance r2 of the failed dry cell is 72Ω

Explanation:

From the circuit diagram attached. We have the electric component:

B1 = 3* 1.58 = 4.74V

B2 = 1.53V

r1 = 3*0.0205 = 0.0615Ω

r2 = 0.105Ω

R = 6.625Ω

Since the internal resistances and the resistor R are connected in series, we can calculate the total resistance RT as

RT = r1 + r2 +R = 0.0615 + 0.105 + 6.625

= 6.7915Ω

Total Voltage supplied to the circuit by both batteries V = B1 + B2 = 4.74 + 1.53 = 6.27V

(a) CIRCUIT CURRENT

The current I, flowing through the circuit is i = $\frac{V}{R_{T}}$ = $\frac{6.27}{6.7915}$ =0.923A

The current in amperes that flows through the toy's circuit is 0.923A

(b) THE POWER SUPPLIED TO THE TOY

Power P = I*V =0.923*6.27 = 5.78721W

The power supplied to the toy is 5.78721W

(c) THE VALUE OF r2

Due to dry cell failure, the power supplied to the toy is reduced to 0.5W

Now Power P = $\frac{V^{2} }{R}$ . To calculate the new total resistance of the circuit we will make R the subject of the formular

R= $\frac{V^{2} }{P}$ = $\frac{6.27^{2} }{0.5}$ = $\frac{39.3129}{0.5}$ = 78.6258Ω

Remember that RT = r1 + r2 + R

r1 =RT- (R +r2)

r1 = 78.6258 - 6.6865 =71.9393Ω

The internal resistance r2 of the failed dry cell is 72Ω

6 0

4 years ago

Read 2 more answers

The data shows that recently the size of the raccoon population decreased. How will the decrease in the raccoon population affec

LenaWriter [7]

Answer: Increase in the population of lower organisms.

Explanation: Raccoons are mesopredators found in the middle levels of food webs and have critical impacts on the dynamics of many other species. Thus, they greatly contribute to the functioning of the ecosystem.

They are naturally equipped to checkmate the population size of other organism that are below them (i.e., their preys) in the food web. They are; predators, pathogen carriers (such as rabies), and competitors, as they compete with some specialist in the food web.

Hence, the decrease in the population of raccoons will lead to the increase in the population size of lower organisms they prey on in the food web or chain.

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3 years ago

In architectural drawings, what do architects use to convey exact details about various parts of a drawing without leaving any s

il63 [147K]

Architects use
marks to identify the exact parts of a building without leaving any scope for misinterpretation.

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4 years ago

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A Capacitor is a circuit component that stores energy and can be charged when current flows through it. A current of 3A flows th

Neko [114]

Answer:

8 μC

Explanation:

By definition, current is the rate of change of charge, so we can write the following equation for current I:

I = ΔQ / Δt

As charge must be conserved, all the charge carried by the current must add to the charge on the plates of the capacitor, so we can finf this incremental charge as follows:

ΔQ = I* Δt (assuming that current remains constant during the charging process)

⇒ ΔQ = 3 A* 2 μsec = 3 coul/sec*2 μsec = 6 μC

As the initial charge must be conserved also, the magnitude of the net electric charge of the capacitor must be as follows:

Qnet = Q₀+ ΔQ = 2 μC + 6 μC = 8 μC

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3 years ago