Answer:
68.8 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) of box = 18 Kg
Coefficient of friction (μ) = 0.39
Force of friction (F) =?
Next, we shall determine the normal force of the box. This is illustrated below:
Mass (m) of object = 18 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal force (N) =?
N = mg
N = 18 × 9.8
N = 176.4 N
Finally, we shall determine the force of friction experienced by the object. This is illustrated below:
Coefficient of friction (μ) = 0.39
Normal force (N) = 176.4 N
Force of friction (F) =?
F = μN
F = 0.39 × 176.4
F = 68.796 ≈ 68.8 N
Thus, the box experience a frictional force of 68.8 N.
Answer:
340.67 kgm²/s
Explanation:
R = Radius of merry-go-round = 1.9 m
I = Moment of inertia = 209 kgm²
= Initial angular velocity = 1.63 rad/s
m = Mass of person = 73 kg
v = Velocity = 4.8 m/s
Initial angular momentum is given by
The initial angular momentum of the merry-go-round is 340.67 kgm²/s
Answer:
0.2286 m, 0.686 m and 1,143 m
therefore we see that there is respect even where the intensity is minimal
Explanation:
Destructive interference to the two speakers is described by the expression
Δr = (2n +1) λ/2
where r is the distance, λ the wavelength and n an integer indicating the order of the interference
let's locate the origin on the left speaker
let's find the wavelength with the equation
v = λ f
λ = v / f
we substitute
Δr = (2n + 1) v / 2f
let's calculate for difference values of n
Δr = (2n +1) 343/(2 750)
Δr = (2n + 1) 0.2286
we locate the different values for a minimum of interim
n Δr (m)
0 0.2286
1 0.686
2 1,143
therefore we see that there is respect even where the intensity is minimal
Answer:
Explanation:
be (in units of Earth-pulls) between a Saturn-like planet and the Sun, if ... ... Sun, If The Planet Is 98 Earth-masses And Is Located At 9.23 AU From The Sun?
Hope this helps! Have a splendid day!
