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murzikaleks [220]
3 years ago
15

Which of the Group 15 elements can lose electron most readily?

Chemistry
1 answer:
ad-work [718]3 years ago
6 0
Bismuth can lose electrons.
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Periodic table 50 elements with thier valancies​
Lubov Fominskaja [6]

Answer:

The first 50 elements along with their valences are given below :

1. Hydrogen = 1

2. Helium = 0

3. Lithium = 1

4. Beryllium = 2

5. Boron = 3

6. Carbon = 4

7. Nitrogen = 3

8. Oxygen = 2

9. Fluorine = 1

10. Neon = 0

11. Sodium = 1

12. Magnesium = 2

13. Aluminium = 3

14. Silicon = 4

15. Phosphorus = 3

16. Sulphur = 2

17. Chlorine = 1

18. Argon = 0

19. Potassium = 1

20. Calcium = 2

21. Scandiun = 3

22. Titanium = 3

23. Vanadium = 4

24. Chromium = 3

25. Manganese = 4

26. Iron = 2

27. Cobalt = 2

28. Nickel = 2

29. Copper = 2

30. Zinc = 2

31. Gallium = 3

32. Germanium = 4

33. Arsenic = 3

34. Selenium = 2

35. Bromine = 1

36. Krypton = 0

37. Rubidium = 1

38. Strontium = 2

39. Yttrium = 3

40. Zirconium = 4

41. Niobium = 3

42. Molybdenum = 3

43. Technetium = 7

44. Ruthenium = 4

45. Rhodium = 3

46. Palladium = 4

47. Sliver = 1

48. Cadmium = 2

49. Indium = 3

50. Tin = 4

<u>Note</u> :

An element like Iron, copper can have more than one valencies.

3 0
3 years ago
Read 2 more answers
Determine all values of hh and k for which the system has no solution
solniwko [45]
Explain more so i could answer it!!
6 0
3 years ago
What is the process of grouping similar things together
andre [41]

Answer:

See Explanation

Explanation:

Mathematically, this means to combine like terms, such as terms with the same variable.  In chemistry, this can refer to polar objects combining with polar objects while nonpolar objects combine with nonpolar objects.

8 0
3 years ago
I need help with this
lubasha [3.4K]
The answer is untestable
5 0
3 years ago
Calculate the molarity of a solution that contains 3.00 grams Na2SO4 in 25 mL of solution.
Naddik [55]

Answer:

M Na2SO4 sln = 0.8448 M

Explanation:

  • molarity (M) [=] mol/L

∴ mass Na2SO4 = 3.00 g

∴ volume soln = 25 mL = 0.025 L

∴ molar mass Na2SO4 = 142.04 g/mol

⇒ mol Na2SO4 = (3.00 g)*(mol/142.04 g) = 0.02112 mol

⇒ M Na2SO4 sln = (0.02112 mol/0.025 L ) = 0.8448 M

3 0
3 years ago
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