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murzikaleks [220]
3 years ago
15

Which of the Group 15 elements can lose electron most readily?

Chemistry
1 answer:
ad-work [718]3 years ago
6 0
Bismuth can lose electrons.
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Study the diagram about the varying pressures of Earth’s Layers.
melomori [17]

Answer:

A) Outer core

Explanation:

just took the test

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3 years ago
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23.It is possible to dilute a solution by...Select one:a. adding more solute to the solution.b. adding more solvent to the solut
joja [24]

To dilute a solute in a solution, it is necessary to add a proper solvent for the reaction to occur, and adding more solvent will cause the solution to dilute even more, therefore the best answer will be letter B

7 0
1 year ago
A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh
Vaselesa [24]

Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

Molarity of NaOH = 0.105 M

Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

3 0
3 years ago
PLZ HELP!!! ILL MARK BRAINLIEST!!! You read an article written by an amateur ghost hunter. It includes the following paragraph.
djverab [1.8K]

No, it is not a scientific claim. If a ghost hunter catches a voice on video like ghost hunters do you can either believe it or not. Ghosts are more of a  i believe it you dont have to type of thing becasue they have not been scientifically proven to exist.

4 0
3 years ago
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Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe]
madreJ [45]

Answer:

Mn^{2+} : - F . [Ar]3d^{5}

Hg^{2+} : - G. [Xe]4f^{14}5d^{10}

La^{3+} : - D. [Xe]

Fe^{3+} : - F. [Ar]3d^{5}

Ag^{+} : - C. [Kr]4d^{10}

Co^{3+} : - E. [Ar]3d^{6}

Explanation:

The electronic configuration of the element Mn is:-

[Ar]3d^{5}4s^2

For, Mn^{2+}, 2 electrons are lost, thus the configuration is:-

[Ar]3d^{5}

The electronic configuration of the element Hg is:-

[Xe]4f^{14}5d^{10}6s^2

For, Hg^{2+}, 2 electrons are lost, thus the configuration is:-

[Xe]4f^{14}5d^{10}

The electronic configuration of the element La is:-

[Xe]5d^{1}6s^2

For, La^{3+}, 3 electrons are lost, thus the configuration is:-

[Xe]

The electronic configuration of the element Fe is:-

[Ar]3d^{6}4s^2

For, Fe^{3+}, 3 electrons are lost, thus the configuration is:-

[Ar]3d^{5}

The electronic configuration of the element Ag is:-

[Kr]4d^{10}5s^1

For, Ag^{+}, 1 electron is lost, thus the configuration is:-

[Kr]4d^{10}

The electronic configuration of the element Co is:-

[Ar]3d^{7}4s^2

For, Co^{3+}, 3 electrons are lost, thus the configuration is:-

[Ar]3d^{6}

7 0
3 years ago
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