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vredina [299]
4 years ago
5

Write and then solve for y = f(x) the differential equation for the statement: "The rate of change of y with respect to x is inv

ersely proportional to y4
Mathematics
1 answer:
vazorg [7]4 years ago
7 0
The statement "<span>The rate of change of y with respect to x is inversely proportional to y^4" can be written mathematically as dy/dx = k/y^4

To solve the differential equation, we use variable saparable method.
y^4 dy = kdx
Integrating both sides gives,
y^5 / 5 = kx + A
y^5 = 5kx + 5A = Bx + C; where B = 5k and C = 5A
y= \sqrt[5]{Bx+C}</span>
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The square root of pi is 1.77245385091.

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2 years ago
PLEASE HELP ASAP!!!!!!!!<br><br> Find the value of the variables.
Korvikt [17]

Answer:

g=79

h=55

j=75

Step-by-step explanation:

1. When a transversal intersects two parallel lines corresponding angles, angles that are located in the same relative position an intersection of transversal and two or more straight lines, are congruent. Therefore g=79.

2. Since the two lines are parallel same side interior angles are supplementary. This means they add up to 180. So to find h solve the equation h+125=180. Once solved you get 55.

3. Like question 2, these angles are same side interior and therefore supplementary. To find j solve the equation j+105=180, which gets j=75.

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3 years ago
Select the correct expressions.
vlabodo [156]

Answer:

9x -9

9(x - 1)

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( Hope this helps ) <(^w^)>

7 0
3 years ago
7. By using binomial expansion show that the value of (1.01)^12 exceed the value of (1.02)^6 by 0.0007 correct to four decimal p
BlackZzzverrR [31]

Binomial expansion is used to factor expressions that can be expressed as the power of the sum of two numbers.

The proof that (1.01)^12 exceeds (1.02)^6 by 0.0007 is\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }

The expressions are given as:

\mathbf{(1.01)^{12}\ and\ (1.02)^6}

A binomial expression is represented as:

\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}

Express 1.01 as 1 + 0.01

So, we have:

\mathbf{(1.01)^{12} = (1 + 0.01)^{12}}

Apply the above formula

\mathbf{(1.01)^{12} = ^{12}C_0 \times 1^{12 - 0} \times 0.01^0 + .........  .......... +  ^{12}C_{12} \times 1^{12 - 12} \times 0.01^{12} }}

\mathbf{(1.01)^{12} = 1 \times 1 \times 1 + .........  .......... +  1 \times 1 \times 10^{-24} }}

\mathbf{(1.01)^{12} = 1  + .........  .......... +  10^{-24} }}

This gives

\mathbf{(1.01)^{12} = 1.1268\ (approximated)}

Similarly,

Express 1.02 as 1 + 0.02

So, we have:

\mathbf{(1.02)^6 = (1 + 0.02)^6}

Apply \mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}

\mathbf{(1.02)^6 = ^6C_0 \times 1^{6 - 0} \times 0.02^0 +  ^6C_1 \times 1^{6 - 1} \times 0.02^1 +.............. + ^6C_6 \times 1^{6 - 6} \times 0.02^6 }\mathbf{(1.02)^6 = 1 \times 1 \times 1 +  6 \times 1 \times 0.02 +.............. + 1 \times 1 \times 6.4 \times 10^{-11} }

\mathbf{(1.02)^6 = 1 +  0.12 +.............. + 6.4 \times 10^{-11} }

This gives

\mathbf{(1.02)^6 = 1.1261\ (approximated) }

Calculate the difference as follows:

\mathbf{(1.01)^{12} - (1.02)^6 \approx 1.1268 - 1.1261 }

\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }

The above equation means that:

(1.01)^12 exceed the value of (1.02)^6 by 0.0007

Read more about binomial expansions at:

brainly.com/question/9554282

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dybincka [34]
20 less then jennifer
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