Answer:
the specimen has 11460 years old
Explanation:
if the live sample has as initial amount of Yo C14, the dead sample will have 0.25Yo of C14.
the rate of decay of radiactive matter over time is
- Y(t) = Yo * e (( - t * Ln2 ) / T)
∴ Y(t) = 0.25Yo; T = 5730
⇒ 0.25Yo = Yo * e (( - t * Ln2 ) / 5730 )
⇒ 0.25 = e (( - t * Ln2 ) / 5730 )
⇒ Ln(0.25) = ( - t * Ln2 ) / 5730
⇒ - 7943.466 = - t * Ln2
⇒ 7943.466 / Ln2 = t
⇒ t = 11460 year
Answer: 1.79 x 10^-5
Explanation: The equilibrium constant of a reaction can be calculated from the quotient of the concentrations of the products over the concentrations of the reactants, with each termed raised to their respective stoichometric coefficients.
For acetic acid, this equilibrium expression is:
![Kc=\frac{[H+] [CH3COO-]}{[CH3COOH]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH%2B%5D%20%5BCH3COO-%5D%7D%7B%5BCH3COOH%5D%7D)
Replacing the equilibrium concentrations given by the exercise into the expression above, the equilibrium constant, Kc will be obtained and it is found to be equal to 1.79 x 10^-5.
Answer:
can be easily broken not as reliable as natural made rubber
Answer:
57.4 g
Explanation:
30.4 g Al will produce 57.4 g Al 2 O 3 30.4 g O 2 will produce 64.6 g Al
2 O 3 .The limiting reagent is aluminum, and the maximum amount of aluminum oxide that can be produced in this reaction is 57.4 g