We have to get the relationship between metallic character and atomic radius.
Metallic character increases with increase in atomic radius and decrease with decrease of atomic radius.
If electrons from outermost shell of an element can be removed easily, that atom can be considered to have more metallic character.
With increase in atomic radius, nuclear force of attraction towards outermost shell electron decreases which facilitates the release of electron.
With decrease in atomic radius, nuclear force of attraction towards outermost shell electrons increases, so electrons are hold tightly to nucleus. Hence, removal of electron from outermost shell becomes difficult making the atom less metallic in nature.
I think is 1 and a half km
277.79 atm is the calculated gas pressure.
The ideal gas is a fictitious concept used to study how real gases behave by comparing them to their deviations. The pressure-temperature rules are followed by an ideal gas.
177 atm is the initial pressure. The starting temperature is 298 K (25 °C = 25 + 273 °C).
195°C = 195+273
= 468K is the final temperature.
The pressure temperature relation illustrated below can be used to get the final pressure.
P1/T1 = P2/T1
= P1T2/T1
= 177 atm 468 K /298 K
= 277.97 atm
The final pressure is therefore 277.97 atm.
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Barium nitride
copy the name of the metal as it is written in the periodic table and the first part of the name of the nonmetal (nitrogen) and replace the end by "ide"
