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spin [16.1K]
2 years ago
7

How many moles of AlCl3 are formed by 1.53 moles of CuCl2?

Chemistry
1 answer:
jolli1 [7]2 years ago
5 0

Answer:

1.02 moles of AlCl3

Explanation:

Consider the balanced reaction equation shown below;

2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)

This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.

Given that;

3 moles of CuCl2 yields 2 moles of AlCl3

1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3

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Which of the following chemical equations is unbalanced? A. 2C + H2 CH4 B. 2Al2O3 4Al + 3O2 C. 2H2O2 2H2O + O2 D. 2C2H6 + 7O2 4C
Tanya [424]

Answer:

A. 2C + H₂ ⟶ CH₄  

Explanation:

A. 2C + H₂ ⟶ CH₄

UNBALANCED. 2C on the left and 1C on the right

B. 2Al₂O₃ ⟶ 4Al + 3O₂  

Balanced. Same number of each type of atom on each side.

C. 2H₂O₂ ⟶ 2H₂O + O₂  

Balanced. Same number of each type of atom on each side.

D. 2C₂H₆ + 7O₂ ⟶ 4CO₂ + 6H₂O

Balanced. Same number of each type of atom on each side.

8 0
3 years ago
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That would be the first option Ca(OH)2 + H2SO4  → CaSO4 + 2H2O.

The Ca replaces the H2 in H2SO4,  and the  H2 replaces the Ca is Ca(OH)2.

8 0
3 years ago
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The diagram shows a carrier wave before and after modulation. The diagram best represents which type of modulation? FM phase AM
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A nuclear power plant operates at 40.0% efficiency with a continuous production of 1042 MW of usable power in 1.00 year and cons
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Answer:

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Explanation:

We know that the formula for Power = Work done (w)/Time (t)

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From the formula P = W/t

W = Power (P) * Time (t)

The SI unit for Time is seconds, hence we change 1 year in seconds

1yr * 365 days/yr * 24hrs/day * 60mins/hr * 60 secs/min = 31536000 secs

It was stated in the question that the plant operates at an efficiency of 40%,

Thus to get the true power we divide the power provided in the question by 0.4 or 40%

= X(0.4) = 1042MW

True Power X = 1042/0.4 = 2605MW

Thus true power = 2605 * 10^6 Watts

Now we have the time in seconds and true power in Watts, we then find the work done.

From our above formula P = W/t

W = P*t = (2605* 10^6) (31536000) =

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