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riadik2000 [5.3K]
2 years ago
15

Help me please!!!!!!!!!!!!

Chemistry
1 answer:
Lisa [10]2 years ago
3 0
PLEASDR PLEASE PLEASE PLEASE PLEASE PLEASE HELP PLEASE PLEASE MAKE PLEASE PLEASE HELP ME PLEASE PLEASE HELP POG PLEASE PLEASE HELP US PLEASE HELP ME HELP ME PLEASE HELP ME THANKS FOR PLE ME PLEASE
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At high pressures how does the volume of a real gas compare with the volume of an ideal gas under the same conditions and why
malfutka [58]
Answer: No, a<span>t high pressures, volume of a real gas does not  compare with the volume of an ideal gas under the same conditions.

Reason: 
For an ideal gas, there should not be any intermolecular forces of interaction. However, for real gases there are intermolecular forces of interaction like dipole-dipole and dipole-induced dipole. Further, at high pressures, molecules are close by. Hence, extend of these intermolecular forces is expected to be high. This results in decreases in volume of real gas. Thus, </span>volume of a real gas does not  compare with the volume of an ideal gas under the same conditions.

3 0
3 years ago
Read 2 more answers
Does the energy go from the surrounding to the chemicals or from the chemicals to the surround in an exothermic reaction?
Karo-lina-s [1.5K]
In general terms, exothermic reactions release energy, so the energy goes from the system to the surroundings.
4 0
3 years ago
Under what conditions does the molar volume of a gas decrease
nydimaria [60]

Answer:

Gases are compressible, meaning that when put under high pressure, the particles are forced closer to one another. This decreases the amount of empty space and reduces the volume of the gas. Gas volume is also affected by temperature. When a gas is heated, its molecules move faster and the gas expands.

4 0
3 years ago
Read 2 more answers
Describe how elements are laid out on the periodic table of elements.
defon

Answer:

The chemical elements are arranged in order of increasing atomic number.

Explanation:

Hydrogen = 1

Helium = 2

Lithium = 3

8 0
3 years ago
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An antacid tablet with an active ingredient of CaCO3 was dissolved in 50.0 mL of 0.300 M HCl. When this solution was titrated wi
yaroslaw [1]

Answer:

Explanation:

mole of HCl remaining after reaction with CaCO₃

= .3 M of NaOH of 32.47 mL

= .3 x .03247 moles

= .009741 moles

Initial HCl taken = .3 x .005 moles = .0015 moles

Moles of HCl reacted with CaCO₃

= .009741 - .0015 = .008241 moles

CaCO₃     +    2HCl   =   CaCl₂  +  CO₂  +  H₂O .

1 mole        2 moles

2 moles of HCl reacts with 1 mole of  CaCO₃

.008241 moles of HCl reacts with .5 x .008241 moles of  CaCO₃

CaCO₃ reacted with HCl =  .5 x .008241 = .00412 moles

the mass (in grams) of calcium carbonate in the tablet

= .00412 x 100 = .412 grams . ( molar mass of calcium carbonate = 100 )

5 0
3 years ago
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