Electromagnetic force is present when electromagnetic fields
2 answers:
Answer:
c- interact with charged particles.
Explanation:
When a charged particle is placed in the field of the other charged particle then it will experience electromagnetic force on it.
As we know that force on a charged particle due to some other electric field is given by
F = qE
here we know
q = charge
E = electric field intensity
Similarly when a charged particle is placed in external magnetic field then the force on that moving charge is given by
so here if charge is moving in the magnetic field due to some other system then the force on it is given by above equation.
So here we can say that electromagnetic force is present when electromagnetic fields
c- interact with charged particles.
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I believe this is what you have to do:
The force between a mass M and a point mass m is represented by
So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁
So F₁ = G(Mm/r^2)
Now the distance has doubled so lets account for this in F₂:
F₂ = G(Mm/(2r)^2)
Now square the 2 that gives you four and we can pull that out in front to give
F₂ = G(Mm/r^2)
Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations
now we see that:
F₂ = F₁
So the second force will be 0.25 (1/4) x 1600 or 400 N.