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Varvara68 [4.7K]
3 years ago
11

A motorcycle (mass of cycle plus rider = 2x 10^2 kg) is traveling at a steady speed of 20 m/s.?The force of air resistance actin

g on the cycle and rider is 2.1 102 N. Find the power necessary to sustain this speed under the following conditions.(a) the road is level W (b) the road is sloped upward at 35° with respect to the horizontal W
Physics
1 answer:
Anna [14]3 years ago
4 0

Answer:

4.2\times10^3 W  

2.67\times 10^4 W    

Explanation:

Given:

Mass of the rider plus the bike, m=2\times10^2 kg

Speed of the motorbike, u= 20 m/s

Force of resistance, F=2.1\times10^2N

Power necessary to sustain speed can be calculated as follows:

1. When road is level

Power = force x velocity  

P= F x u

P=(2.1\times10^2N)(20 m/s) = 4.2\times10^3 W

2. When the road is sloped at an angle 35°

An additional force will act due to component of gravity that is

= mg sin \theta

So,

P = (F+mgsin\theta)u\\ P= (2.1\times10^2+2\times10^2\times 9.8 \times sin35^o)(20)=2.67\times 10^4 W

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We must take in consideration that two parts with same mass do not move in same direction. The center of mass of these two parts moves between them at angle of 45° with respect to both south and west. The speed of a center of mass is:
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3 years ago
Read 2 more answers
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