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Varvara68 [4.7K]

3 years ago

11

A motorcycle (mass of cycle plus rider = 2x 10^2 kg) is traveling at a steady speed of 20 m/s.?The force of air resistance actin

g on the cycle and rider is 2.1 102 N. Find the power necessary to sustain this speed under the following conditions.(a) the road is level W (b) the road is sloped upward at 35° with respect to the horizontal W

1 answer:

Anna [14]3 years ago

4 0

Answer:

$4.2\times10^3 W$

$2.67\times 10^4 W$

Explanation:

Given:

Mass of the rider plus the bike, $m=2\times10^2 kg$

Speed of the motorbike, u= 20 m/s

Force of resistance, $F=2.1\times10^2N$

Power necessary to sustain speed can be calculated as follows:

1. When road is level

Power = force x velocity

P= F x u

$P=(2.1\times10^2N)(20 m/s) = 4.2\times10^3 W$

2. When the road is sloped at an angle 35°

An additional force will act due to component of gravity that is

$= mg sin \theta$

So,

$P = (F+mgsin\theta)u\\ P= (2.1\times10^2+2\times10^2\times 9.8 \times sin35^o)(20)=2.67\times 10^4 W$

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$b=\frac{mg-ma}{v}; m=\frac{F+kx}{g*cos(o)}$

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The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N

<h3>Data obtained from the question </h3>

Initial velocity (u) = 8.5 m/s
Final velocity (v) = 7.5 m/s
Time (t) = 5 ms = 0.25 s
Mass (m) = 2.5 Kg
Force (F) = ?

<h3>How to determine the force</h3>

The force exerted on the ball can be obtained as follow:

F = m(v + u) / t

F = [2.5(7.5 + 8.5)]/ 0.25

F = 40 / 0.25

F = 160 N

Thus, the force exerted on the ball is 160 N

Learn more about momentum:

brainly.com/question/250648

#SPJ1

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