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Marysya12 [62]
3 years ago
7

A small electronic device is rated at 0.16 W when connected to 115 V. What is the resistance of this device?

Physics
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

150156.25 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of electric current in a circuit. The S.I unit of resistance is Ohm's (Ω)

The expression for resistance is given as

P = V²/R................ equation 1

Where P = power, V = Voltage, R = Resistance.

Making R the subject of the equation,

R = V²/P.................. Equation 2

Given: V = 115 V , P = 0.16 W.

Substitute into equation 2

R = 155²/0.16

R = 150156.25 Ω

Hence,

The resistance = 150156.25 Ω

murzikaleks [220]3 years ago
8 0

Answer:

82.656 KΩ

Explanation:

The power rating (P) in a device is related to its voltage (V) and its resistance (R) as follows;

P = \frac{V^{2} }{R}    ------------------------(i)

Where, according to the question;

P = 0.16W

V = 115V

R is unknown

<em>Substitute the values of P and V into the equation (i);</em>

=> P = \frac{V^{2} }{R}

=> 0.16 = 115^{2} / R

<em>Make R subject of the formula</em>

=> R = \frac{115^{2} }{0.16}

=> R = 13225 / 0.16

=> R = 82656.25Ω

=> R = 82.656KΩ

<em>The resistance of the device is R = 82.656KΩ</em>

<em></em>

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