Answer:
fundamental frequency of pipe will be equal to 74 Hz
Explanation:
We have given for a particular organ pipe two adjacent frequency are 296 Hz and 370 Hz
Speed of the sound in air is 343 m/sec
We have to find the fundamental frequency for the pipe
Fundamental frequency will be equal to difference of the two adjacent frequency
So fundamental frequency = 370 - 296 = 74 Hz
So fundamental frequency of pipe will be equal to 74 Hz
Answer:
1. Emma standing on top of mountain
Since she is at the rest position and at some height from the ground so here energy is due to gravitational potential energy
So we have
gravitational potential energy
![U = mgH](https://tex.z-dn.net/?f=U%20%3D%20mgH)
2. Emma jumping down from mountain top
Due to free fall Emma will start moving with some speed in downwards direction so here we have
![KE = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
motion energy
3. tension in rope at Emma’s lowest position
Due to stretch in the rope here position come to the lowest end and speed comes to zero so whole energy is converted into elastic potential energy
![U = \frac{1}{2}kx^2](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7B1%7D%7B2%7Dkx%5E2)
elastic potential energy
4. Emma bouncing back
Due to bouncing back she will again have its kinetic energy with some speed upwards
![KE = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
motion energy
Answer:
3500N
Explanation:
Given parameters:
Mass of driver = 50kg
Speed = 35m/s
Time = 0.5s
Unknown:
Average force the seat belt exerts on her = ?
Solution:
The average force the seat belt exerts on her can be deduced from Newton's second law of motion.
F = mass x acceleration
So;
F = mass x ![\frac{change in velocity }{time}](https://tex.z-dn.net/?f=%5Cfrac%7Bchange%20in%20velocity%20%7D%7Btime%7D)
F = 50 x
= 3500N