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Novay_Z [31]
3 years ago
8

An object is placed 45 cm in front of a crystal ball. The crystal ball has a radius of 14 cm, and is made from a glass with an i

ndex of refraction of n = 1.5.
Find the position of the final image once the rays have gone through the two faces, as measured from the second face. Is a virtual object formed anywhere in the analysis? Yes or no
Physics
1 answer:
abruzzese [7]3 years ago
6 0

Answer:

Explanation:

 Using the formula for refraction at curved surface

For refraction at first surface

μ₂ /v -μ₁ /u = ( μ₂ - μ₁ )/R

1.5/v -1/-45 =.5/14

v = 111 cm

For refraction at opposite surface ,

u ( object distance ) = 111 - 28 =83 cm

It will act as virtual object for surface 2 so it will be positive in sign

again using the above equation for 2 nd surface we have

1/v - 1.5/83.17 = -.5-=/-14 = 1/28

v = 18.62 cm from second face.

yes, virtual image will be formed.

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A calcium-40 ion has a positive charge that is double the charge of a proton, and a mass of 6.64 ✕ 10−26 kg. At a particular ins
Zina [86]

Answer:

Detailed solution is given below

4 0
3 years ago
1. Is there a relationship between the volume of water displaced and the total volume of the block that has anything to do with
strojnjashka [21]

Answer:

The volume of the block is equal to the volume of water displaced by the block.

Explanation:

Volume refers to the amount of space occupied by a given object (in this case the block). When an object such as the block is immersed in water, it displaces its own volume of water. This volume of water displaced is equal to the volume of the block. Hence we can write;

Final Volume of water - Initial Volume of water= Water Displaced = Volume of the block

Recall that the density of a body is given by;

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If we obtain the volume of the block by measuring the volume of water displaced by the block, then we weigh the block using a weighing balance, we can obtain the density of the block easily from the relationship shown above.

8 0
2 years ago
How much work must be done to stop a 1100-kg car traveling at 112 km/h?(Hint: You will need to convert the speed first.)Answer:
zimovet [89]

According to the Work-Energy Theorem, the work done on an object is equal to the change in the kinetic energy of the object:

W=\Delta K

Since the car ends with a kinetic energy of 0J (because it stops), then the work needed to stop the car is equal to the initial kinetic energy of the car:

K=\frac{1}{2}mv^2

Replace m=1100kg and v=112km/h. Write the speed in m/s. Remember that 1m/s = 3.6km/h:

\begin{gathered} K=\frac{1}{2}(1100kg)\left(112\frac{km}{h}\times\frac{1\frac{m}{s}}{3.6\frac{km}{h}}\right)^2=532,345.679...J \\  \\ \therefore K\approx532,346J \end{gathered}

Therefore, the answer is: 532,346 J.

5 0
1 year ago
It is now 9:11 a.m. but when the bell rings at 9:12 a.m. Susie will be late for Mrs. Garner's U.S. History class for the 3rd tim
GaryK [48]

Answer:

3.1 m/s

Explanation:

The total distance she has to run is the addition of the three lengths:

47 + 63 + 76 = 186 meters.

She needs to cover it one minute (60 seconds). Therefore her speed must be:

186 m / 60 s = 3.1 m/s

6 0
3 years ago
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