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AysviL [449]
4 years ago
13

If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s. How long is the ball in fr

ee fall?​
Physics
1 answer:
enot [183]4 years ago
4 0

Answer:

<h3>3.06s</h3>

Explanation:

If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s,we ae to find the time taken for the ball to drop. To do that we will use the equation of motion v = u + gt

v is the final velocity = 30m/s

u is the initial velocity = 0m/s (the object drops from rest)

g is the acceleration due to gravity = 9.81m/s²

time is the time taken

Substituting the given parameters into the formula;

30 = 0 + (9.81)t

30 = 9.81t

t = 30/9.81

t = 3.06secs

<em></em>

<em>Hence it will take the object 3.06secs in free fall</em>

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An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa
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Answer:

1.38*10^18 kg

Explanation:

According to the Newton's law of universal gravitation:

F=G*\frac{m_a*m_p}{r^2}

where:

G= Gravitational constant (6.674×10−11 N · (m/kg)2)

ma= mass of the astronaut

mp= mass of the planet

F=m_a.a\\(v_f )^2=(v_o)^2+2.a.\Delta y\\\\a=\frac{(v_f)^2-(v_o)^2}{2.\Delta y}\\\\a=\frac{(0)^2-(4.29m/s)^2}{2.0.64m}=14.38m/s^2\\\\F=m_a*14.38m/s^2

so:

m_a*14.38m/s^2=(6.674*10^{-11}N.(m/kg)^2)*\frac{m_a.m_p}{(2.530*10^3m)^2}\\m_p=\frac{14.38m/s^2(2.530*10^3m)^2}{(6.674*10^{-11}N.(m/kg)^2)}\\\\m_p=1.38*10^{18}kg

7 0
4 years ago
6–23 an automobile engine consumes fuel at a rate of 22 l/h and delivers 55 kw of power to the wheels. if the fuel has a heating
Anna007 [38]

Explanation & answer:

Given:

Fuel consumption, C = 22 L/h

Specific gravity = 0.8

output power, P  =  55 kW

heating value, H = 44,000 kJ/kg

Solution:

Calculate energy intake

E = C*P*H

= (22 L/h) / (3600 s/h) * (1000 mL/L) * (0.8 g/mL) * (44000 kJ/kg)

= (22/3600)*1000*0.8*44000 j/s

= 215111.1 j/s

Calculate output power

P = 55 kW

= 55000 j/s

Efficiency

= output / input

= P/E

=55000 / 215111.1

= 0.2557

= 25.6% to 1 decimal place.

8 0
3 years ago
a man uses a 900 watt electric iron to press his clothes for an average of 4 hours a week for five weeks if the cost of an elect
ser-zykov [4K]

Answer:

54 Kobo

Explanation:

Units of <u>electricity</u> are measured in kilowatt hours (kWh).

Given information:

  • 900 watt electric iron
  • Appliance usage = 4 hours a week for 5 weeks
  • Unit cost of electricity = 3 Kobo per kWh

<h3><u>Step 1</u></h3>

Convert the wattage of the electric iron from watts to kilowatts.

1000 watts (W) = 1 kilowatt (kW)

⇒ 900 watts = 1 ÷ 1000 = 0.9 kilowatts

This means that the power consumption of the electric iron is 0.9 kW per hour of use.

<h3><u>Step 2</u></h3>

Total hours spent pressing clothes:

= 4 hours per week for 5 weeks

= 4 × 5

= 20 hours

<u>Total power consumption</u>:

= number of kW × number of hours

= 0.9 × 20

= 18 kWh

<h3><u>Step 3</u></h3>

To find the <u>total cost</u>, multiply the total kWh by the cost per kWh:

⇒ Cost = 18 × 3 = 54 Kobo

4 0
2 years ago
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Answer: 110000

Explanation:

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30.5555555556 x 60=1833.33333333

110000 x 60=110000

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