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3 years ago

A 0.413 kg block requires 1.09 N

Physics

1 answer:

Virty [35]3 years ago

5 0

Answer:

Explanation:

The equation for this is

f = μ $F_n$ where f is the frictional force the block needs to overcome, μ is the coefficient of static friction, and $F_n = w=mg$ (that means that the normal force is the same as the weight of the block which has an equation of weight = mass times the pull of gravity). Filling in:

1.09 = μ(.413)(9.8) and

μ = $\frac{1.09}{(.413)(9.8)}$ so

μ = .27

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