A 0.413 kg block requires 1.09 N
1 answer:
Answer:
Explanation:
The equation for this is
f = μ where f is the frictional force the block needs to overcome, μ is the coefficient of static friction, and
(that means that the normal force is the same as the weight of the block which has an equation of weight = mass times the pull of gravity). Filling in:
1.09 = μ(.413)(9.8) and
μ = so
μ = .27
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Answer:
The amount of mass that needs to be converted to release that amount of energy is
Explanation:
From Albert Einstein's Energy equation, we can understand that mass can get converted to energy, using the formula
where = change in mass
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Answer:
The value of gauge pressure at outlet = -38557.224 pascal
Explanation:
Apply Bernoulli' s Equation
+
+
=
+
+
--------------(1)
Where
= Gauge pressure at inlet = 3.70105 pascal
= velocity at inlet = 2.4
= Gauge pressure at outlet = we have to calculate
= velocity at outlet = 3.5
= 3.6 m
Put all the values in equation (1) we get,
⇒ +
=
+
+ 3.6
⇒ 0.294 = + 0.6244 + 3.6
⇒ = 0.294 - 0.6244 - 3.6
⇒ = - 3.9304
⇒ = - 38557.224 pascal
This is the value of gauge pressure at outlet.