A 0.413 kg block requires 1.09 N
1 answer:
Answer:
Explanation:
The equation for this is
f = μ where f is the frictional force the block needs to overcome, μ is the coefficient of static friction, and
(that means that the normal force is the same as the weight of the block which has an equation of weight = mass times the pull of gravity). Filling in:
1.09 = μ(.413)(9.8) and
μ = so
μ = .27
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Answer: A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. Energy loss will be 0.29J
Explanation: To find the correct answer, we have to know more about the Gravitational potential energy.
<h3>What is gravitational potential energy?</h3>- The energy possessed by a body by virtue of its position in gravitational field of earth is called gravitational potential energy.
- The gravitational potential energy of a body at a height h with respect to the height h will be,
- Expression for gravitational potential energy loss will be,
- The total energy before the ball dropped will be,
- The total energy after when the ball rebounds to 1.5m will be,
- The total energy loss will be,
Thus, we can conclude that, the energy loss will be,0.294J.
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Answer:
Speed of water at the top of fall = 5.40 m/s
Explanation:
We have equation of motion
Here final velocity, v = 26 m/s
a = acceleration due to gravity
displacement, s = 33 m
Substituting
Speed of water at the top of fall = 5.40 m/s