Answer:
By bonding due to the attractive forces
The molecular formula<span> add the structure to a </span>empirical formula<span>. A </span>molecular formula<span> is identical to the </span>empirical formula<span>, and is based on quantity of atoms of each type in the </span>compound<span>.</span>
Answer:
the osmolarity of the 0.85% NaCl solution is approximately equal to 300 mosmol/L.
Explanation:
Molarity= number of moles/volume of the solution in liters
volume of the solution= 100 mL
1 L= 1000 mL
100 mL= 100/1000=0.1 L
molar mass of NaCl= 58.44 g/mol
number of moles= mass in gram/gram molecular mass
= 0.85/58.44
= 0.01455
molarity= number of moles/volume of the solution in liters
= 0.01455 / 0.1
= 0.1455 M
1 M= 1000 mM
so 0.1455 M = 0.1455 × 1000
= 145.5 mM
Osmolarity is the concentration of solutes in the solution.
NaCl dissociates to Na+ and Cl-
so osmolarity of 145.5 mM NaCl= 2 × 145.5
= 291 mosmol/L
Therefore, we conclude that the osmolarity of the 0.85% NaCl solution is approximately equal to 300 mosmol/L.
1. Compound 2. Diatomic 3. Molecules 4. Compound 5. Structure
count the elements in eqn MgI2 + Br2 -> MgBr2 + I2
1 Mg, 2I, 2Br on the left n
1 Mg, 2I, 2Br on the right
they are equal so the eqn is balanced