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Harman [31]
3 years ago
7

Planet X has no atmosphere. This planet will most likely _____.

Physics
3 answers:
aniked [119]3 years ago
8 0
C) have many craters from meteoroids
TiliK225 [7]3 years ago
6 0
A) be too hot to support life
Hope dis helps! :3
eduard3 years ago
5 0

A) be too hot to support life

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In a related practical activity, 2 litres of a gas were heated from 35 °C to 75 °C. If the pressure was kept constant, calculate
Pachacha [2.7K]

Answer:

2.26l

Explanation:

From the general gas equation:

P1V1/T1  = P2V2/T2

Since pressure remained constant we can say:

V1/T1  = V2/T2

so to convert to kelvin add 273 to both temperature values then we can say:

1 m^3= 1000 L

2l=0.002m^3

Then;

0.002/308=V/348

V=(0.002/308)348

Final volume=0.002259m^3

=2.6l(1 decimal place)

4 0
1 year ago
What happens to the atomic number of an atom when the number of neutrons in the nucleus of that atom increases? a It decreases b
kupik [55]

Answer:

It remains the same

Explanation:

It remains the same. This is because the number of protons doesn't change and the number of protons determines the atomic number.

8 0
2 years ago
What is the chemical formula for mercury(I) nitrate? Hgmc021-1.jpg(NOmc021-2.jpg) Hg(NOmc021-3.jpg)mc021-4.jpg Hgmc021-5.jpg(NOm
Anit [1.1K]
If you just type "<span>What is the chemical formula for mercury(I) nitrate?" into google you get the answer but HG(NO3)2 is the correct one.
sorry no one helped you in time hope you passed anyway</span>
8 0
3 years ago
Read 2 more answers
A student has designed a circuit with one battery, two light bulbs, and two switches, pictured to the left. She would like for e
Gnoma [55]

Answer:

The bulb is not powered because the negative end of the battery is not connected to the electric current,making it dysfunctional. The electrons have to flow through the positive and negative ends of the battery in order for it to work.

Hope this helps.

5 0
3 years ago
Read 2 more answers
A coil of 40 turns is wrapped around a long solenoid of cross-sectional area 7.5×10−3m2. The solenoid is 0.50 m long and has 500
defon

To solve this problem it is necessary to apply the concepts related to mutual inductance in a solenoid.

This definition is described in the following equation as,

M = \frac{\mu_0 N_1 N_2A_1}{l_1}

Where,

\mu =permeability of free space

N_1 = Number of turns in solenoid 1

N_2 = Number of turns in solenoid 2

A_1= Cross sectional area of solenoid

l = Length of the solenoid

Part A )

Our values are given as,

\mu_0 = 4\pi *10^{-7}H/m

N_1 = 500

N_2 = 40

A = 7.5*10^{-4}m^2

l = 0.5m

Substituting,

M = \frac{\mu_0 N_1 N_2A_2}{l_1}

M = \frac{(4\pi *10^{-7})(500)(40)(7.5*10^{-4})}{0.5}

M = 3.77*10^{-4}H

PART B) Considering that many of the variables remain unchanged in the second solenoid, such as the increase in the radius or magnetic field, we can conclude that mutual inducantia will appear the same.

8 0
3 years ago
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