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3 years ago

ASAP answer all pls will mark brainiest

Physics

2 answers:

sammy [17]3 years ago

7 0

Answer:

1) B

2)D

Explanation:

I am unsure of #2

Brilliant_brown [7]3 years ago

5 0

1)C momentum is definitely a property just like inertia
2)D momentum = mass x energy = 9 x 3 = 27

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Calculate the power transfer when a pump moves 50kg of water through a vertical height of 8meters in 5seconds (take g =10meters

Vika [28.1K]

Hi there!

Recall the following relationships:

$W = \Delta U = mg\Delta h\\\\P = \frac{W}{t}$

W = Work (J)

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height (m)

t = time (s)

Begin by calculating the work:

$W = 50(10)(8) = 4000 J$

Now, divide by the time to solve for power:

$P = \frac{4000}{5} = \boxed{800W}$

**W is the unit for power (Watts). Be careful not to get the two confused.

4 0

3 years ago

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olganol [36]

Answer:A, Concave

Explanation:

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4 years ago

Clear cutting has a similar effect as controlled burning of a forest. True False

mariarad [96]

Clear cutting has a similar effect as controlled burning of a forest is True.

True

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3 years ago

Read 2 more answers

A wire of length L and cross-sectional area A has resistance R.

Leona [35]

Answer:

The resistance R stretched of the wire if it is stretched to twice its original length is [Δ(2L) / A ]* 2

Explanation:

Original Resistance R = ΔL / A

Given length is doubled

New length L' = 2L

New Volume is constant, resistivity and density of material is also assumed to be constant

AL = A'L'

AL = A'(2L)

A' = AL / 2L

A' = A / 2

∴ new Resistance R' = ΔL' / A'

= Δ(2L) / A/2

= [Δ(2L) / A ]* 2

6 0

3 years ago

In a cricket match, the 0.16kg ball is bowled with a straight arm. During one particular delivery, the ball leaves the bowler's

Papessa [141]

Answer:

412.1 N

Explanation:

First of all let's calculate the total speed of the ball as it is released, which is equal to the speed of the ball + the speed of the bowler:

$v=80.8 mph +10.0 mph=90.8 mph$

Now let's convert it into m/s. We know that

$1 mph = 0.447 m/s$

$1 mph:0.447 m/s = 90.8 mph:v\\v=\frac{(0.447 m/s)(90.8 mph)}{1 mph}=40.6 m/s$

And now we can calculate the centripetal force, which is given by:

$F=m\frac{v^2}{r}$

where

m = 0.16 kg is the mass of the ball

v = 40.6 m/s is the speed of the ball

r = 0.64 m is the radius of the circular path (equal to the length of the bowler's arm)

Substituting:

$F=(0.16 kg)\frac{(40.6 m/s)^2}{0.64 m}=412.1 N$

6 0

4 years ago