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Free_Kalibri [48]
3 years ago
14

A 0.155 kg arrow is shot upward

Physics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer: 244.05 J

Explanation:

To find speed  at 30 m above the ground use equation:

V²=Vo²-2Gs

V0=31.4m/s

s=30m

G=9.81m/s²

-----------------------

V²=31.4²-2*9.81*30

V²=985.96+588.6

V²=1574.56

V=39.68m/s ---speed of arrow on 30 m obove the ground

Use equation for kinetic enrgy:

Ke=mV²/2

m=0.155kg

V=39.68m/s

-------------------------

Ke=0.155kg*(39.68m/s)²/2

Ke=0.155*1574.5/2

Ke=244.05J

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According to the question

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A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red
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In this case, the Doppler effect equation in terms of wavelength is :

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555\times10^{-9} } = 660\times10^{-9} \sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }

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