E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15
Bayes' theorem is transforming preceding probabilities into succeeding probabilities. It is based on the principle of conditional probability. Conditional probability is the possibility that an event will occur because it is dependent on another event.
P(F|E)=P(E and F)÷P(E)
It is given that P(E)=0.3,P(F|E)=0.5
Using Bayes' formula,
P(F|E)=P(E and F)÷P(E)
Rearranging the formula,
⇒P(E and F)=P(F|E)×P(E)
Substituting the given values in the formula, we get
⇒P(E and F)=0.5×0.3
⇒P(E and F)=0.15
∴The correct answer is 0.15.
If, E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15.
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Let x = the smaller numberLet 3x + 15 = the larger numberx + 3x + 15 = 634x = 48x = 123(12) + 15 = 51
Your answer would be R=-5x-4+y
Step-by-step explanation:
(23/5)÷(-33/4)
multiply the first by the second reverse
23/5×4/-33
multiply the numerator between them and the denomination between them
92/-165
-0.558
