Answer:
depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
Step-by-step explanation:
- First calculate the amount of depreciation/ton
- depreciation per ton = $125,000/208,000 = $0.600 /ton
- Hence depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
5 times the quotient of 2 numbers is 5(r/t)
Answer is the third option
5(r/t)
C 7/8
With the graph, you add the values of the X's together and find the mean (divide by 8)
(0.25+0.5+0.5+0.5+1+1+1.5+1.75)/8
7/8
Simplified expression is 6y² - 24y - 51. Value for y=-2 is 21 and value for y=3 is -69.
Step-by-step explanation:
- Step 1: Given expression is 3y(2y-7) - 3(y - 4) - 63. Simplify it.
⇒ 6y² - 21y - 3y + 12 - 63
⇒ 6y² - 24y - 51
- Step 2: Find value of the expression for y = -2
⇒ 6y² - 24y - 51 = 6(-2)² - 24(-2) - 51 = 24 + 48 - 51 = 21
- Step 3: Find value of the expression for y = 3
⇒ ⇒ 6y² - 24y - 51 = 6(3)² - 24(3) - 51 = 54 - 72 - 51 = -69
