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kati45 [8]
3 years ago
12

Two lightweight rods 24 cm in length are mounted perpendicular to an axle and at 180 ∘ to each other. At the end of each rod is

a 480-g mass. The rods are spaced 42 cm apart along the axle. The axle rotates at 5.0 rad/s. (a) What is the component of the total angular momentum along the axle? (b) What angle does the vector angular momentum make with the axle? [Hint: Remember that the vector angular momentum must be calculated about the same point for both masses, which could be the cm.]
Physics
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer:

Explanation:

Angular momentum ( L ) = moment of inertia x angular velocity ( I X ω )

Moment of inertia of two  480 g masses about axle = 2 x mr²  = 2 x 480 x10⁻³ x( 24 x 10 ⁻ 2 )²  = 0. 552960  kg m².

Angular velocity = 5 rad / s.

Angular momentum = 0.552960 x 5 = 2.765 kg m2.

The direction of angular momentum will be along axle.So vector angular

momentum  makes zero degree  with axle.

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Fernanda is working on a physics project. she is experimenting by rolling a marble down a ramp and then seeing how far it rolls
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The distance covered on the floor after leaving the ramp is the dependent variable.

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In any experiment, the dependent variable must be measured or determined, and it must change as the independent variable does.

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A window in a skyscraper has a surface area of 3.50 m^2. Wind rushes by the outside of the window at 17.4 m/s, while inside the
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The given data in the problem is;

dP is the change in the presure=?

Using Bernoulli's Theorem;

\rm  \rho\frac{V^2_{12}}{2} +P_1= \rho \frac{V^2_{22}}{2} +P_2 \\\\\ P_2-P_1=\rho \frac{v_2^2-v_1^2}{2} \\\\  P_2-P_1= 1.21 \times \frac{17.4^2-0}{2} \\\\  \triangle p=369.36 \ N/m^2

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Case d) has the strongest gravitational force

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