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2 years ago

A) what is hydrogen's carrying capacity? b) what is lithium’s carrying capacity?

Chemistry

1 answer:

sladkih [1.3K]2 years ago

3 0

Answer:

A)Hydrogen can be stored physically as either a gas or a liquid. Storage of hydrogen as a gas typically requires high-pressure tanks (350–700 bar [5,000–10,000 psi] tank pressure). Storage of hydrogen as a liquid requires cryogenic temperatures because the boiling point of hydrogen at one atmosphere pressure is −252.8°C.

B) carrying capacity of the lithium reserve will reach 10 million EV and 90 billion CE's RLBs for 50% recycling of lithium-containing waste, and 15 million EV and 150 billion CE's RLBs for 90% recycling.

Explanation:

Hope this helped Mark BRAINLEST!!

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a bowl of cereal is at a temperature of 62 fahrenheit then the bowl of cereal thermal energy decreases as soon as mass or not ch

rewona [7]

<h3>Answer:</h3>

53 fahrenheit

<h3>Explanation:</h3>

Temperature is a measure of thermal energy. It goes down when thermal energy decreases. Of your choices, the temperature lower than 62 °F is 53 °F.

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3 years ago

How much energy is absorbed in breaking up the water molecules?

tiny-mole [99]

Answer:

1852 kJ/mol

Explanation:

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2 years ago

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miv72 [106K]

Answer:

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Explanation:

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2 years ago

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A tank in the shape of a rectangular prism measures 10 dm by 4 dm by 6 dm. the tank is completely filled with 8908.8 l of liquid

nevsk [136]

1) The question contains an unknown unit

The number 8908.8 has to be in units of mass: for example, kg or grams.

Here you indicated L.

I am going to work assuming that L is a mass unit. So you can see the way to solve the problem, but you have to verifiy the real unit of the statement and substitute with it.

With that in mind you can find the density of the liquid from:

density = mass / volume

2) Calculate the volume.

The volume of the liquid is the volume of the vessel, because it is filled.

The volume of the vessel is calculated from the formula of volume for a rectantular prism.

Volume of a rectangular prism = area of the base * height = side * side * height

=> Volume = 10 dm * 4 dm * 6 dm = 240 dm^3 = 240 liter

3) Calculate the density:

density = mass /volume = 8,908.8 L / 240 liter = 37.12 L / dm^3

Answer: 37.12 L / dm^3

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3 years ago

Suppose a 250. mL flask is filled with 0.30 mol of N_2 and 0.70 mol of NO. The following reaction becomes possible:N_2(g) +O2 →

Inessa [10]

Answer:

0.4 M

Explanation:

Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.

Because there's no O₂ in the beginning, the NO will decompose:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.30 0 0.70 Initial

+x +x -2x Reacts (the stoichiometry is 1:1:2)

0.30+x x 0.70-2x Equilibrium

The equilibrium concentrations are the number of moles divided by the volume (0.250 L):

[N₂] = (0.30 + x)/0.250

[O₂] = x/0.25

[NO] = (0.70 - 2x)/0.250

K = [NO]²/([N₂]*[O₂])

K = $\frac{(\frac{0.70 -2x}{0.250})^2 }{\frac{0.30+x}{0.250}*\frac{x}{0.250} }$

7.70 = (0.70-2x)²/[(0.30+x)*x]

7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)

4x² - 2.80x + 0.49 = 2.31x + 7.70x²

3.7x² + 5.11x - 0.49 = 0

Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70

x = 0.09 mol

Thus,

[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M

3 0

3 years ago