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stira [4]
3 years ago
15

When a person in the hospital is given fluids intravenously, the fluid is typically a saline (salt) solution with about the same

water concentration as human body tissues. Explain how the use of distilled water (water without salt) in place of this saline solution would possibly upset the patients homeostasis.
Chemistry
1 answer:
Sati [7]3 years ago
5 0

Answer:

Swelling of the red blood cells occurs.

Explanation:

  • <u>Distilled water makes the blood hypotonic ,. that is a less concentrated solution, to the body  tissues including  the red blood cells. </u>
  • Therefore the water will enter the red blood cells and may cause them to lyse or swell.
  • <em>Additionally , water will enter the tissue spaces and cause sweling. </em>
  • But in the case of a hypertonic solution , ( a salt or saline solution ) , <em>This swelling does not happen because the concentration of the saline will be equal or more than the blood. </em>
  • Thus the water will flow only from the blood to the solution. <u>This will not cause swelling.</u>
  • But too much of salt is also not recommended.
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T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of pure carbon disulfide= 46.2^oC

k_b = boiling point constant  =2.34^0Ckg/mol

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute = 35.0 g

w_1 = mass of solvent (carbon disulphide) = 397.7 g

M_2 = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}

T_b=49.1^0C

Therefore, the change in boiling point is (49.1-46.2)^oC=2.9^0C

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