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balu736 [363]
3 years ago
10

Which statement best describes how organisms demonstrate the transformation of energy?

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
8 0

O Light energy from the Sun is converted into mechanical energy in a deer, which produces waste that is absorbed by a wildflower to produce chemical energy

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Which choice gives the correct oxidation numbers for all three elements in rb2so3 in the order that the elements are shown in th
vlabodo [156]
<h3>Answer:</h3>

             Rb  =  + 1

              S    =  + 4

              O   =  - 2

<h3>Explanation:</h3>

                   Oxidation states of the elements were calculated keeping in mind the basic rules of assigning oxidation states which included assignment of +1 charge to first group elements i.e. Rubidium (Rb) and assignment of -2 charge to Oxygen atom. Then the oxidation state of Sulfur was calculated as follow,

Rb₂ + S + O₃  =  0

Above zero (0) means that the overall molecule is neutral.

Putting values of Rb and O,

                                           (+1)₂ + S + (-2)₃  =  0

                                           (+2) + S + (-6)  =  0

                                           +2 + S - 6  = 0

                                           S - 6  =  -2

                                          S  =  -2 + 6

                                           S  =  + 4

7 0
3 years ago
The following information was recorded by a student team working to prepare nickel sulfate. Plan: Prepare NiSO4 by reacting NiO
mixas84 [53]

Answer:

The options e and d are correct.

Explanation:

Mass of NiO = 7.5 g

Moles of NiO = \frac{7.5 g}{74.69 g/mol}=0.10 mol

Moles of sulfuric acid = n

Volume of sulfuric acid ,V= 50 mL = 0.050 L

Molarity of sulfuric acid ,M = 6 mol/L

n=M\time V=6mol/L\times 0.050 L =0.3 mol

NiO + H_2SO_4\rightarrow NiSO_4 + H_2O

According to reaction, 1 mole of NiO reacts with 1 mole of sulfuric acid.

Then 0.10 moles of NiO reacts with :

\frac{1}{1}\times 0.10 mol/=0.10 mol of sulfuric acid.

As we can see that sulfuric acid is in excess amount, so the amount of the product will depend upon amount of NiO.

According to reaction, 1 mole of NiO gives with 1 mole of NiSO_4.

Then 0.10 moles of NiO wil give :

\frac{1}{1}\times 0.10 mol/=0.10 mol of  NiSO_4.

Molar mass of  NiSO_4 = 154.75 g/mol

Mass of 0.10 moles of NiSO_4:

= 154.75 g/mol × 0.10 mol = 15.475 g

Theoretical mass of NiSO_4 = 15.475 g

Experimental yield of NiSO_4 = 17.4 g

Percentage yield :

\Yield=\frac{\text{Experimental mass}}{\text{Theoretical mass}}\times 100

Percentage yield of NiSO_4:

\Yield=\frac{17.4}{15.475 g}\times 100=112\%

Moles of NiSO_4.6H_2O = 262.85 g/mol × 0.10 mol = 26.285 g

Experimental yield of NiSO_4.6H_2O = 17.4 g

Percentage yield of NiSO_4.6H_2O:

\Yield=\frac{17.4}{26.285 g}\times 100=66.2\%

3 0
3 years ago
Did I do this science worksheet correctly? Asking for a friend
grin007 [14]

Yes everything looks good to me

8 0
3 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 27.0c
Alla [95]

We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.

The final temperature is: 75.11 °C.

The work done at constant pressure, W=nR(T₂-T₁)

n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).

W=2.4 × 10³ Joule (Given)

From the expression,

(T₂-T₁)=\frac{W}{nR}

(T₂-T₁)= \frac{2.40 X 10^{3} }{6 X 8.314}

(T₂-T₁)= 48.11

T₂=300+48.11=348.11 K= 75.11 °C

Final temperature is 75.11 °C.


6 0
3 years ago
Describe use of H₂S an analytical reagent?<br><br>​
Gemiola [76]

Answer:

The main use for hydrogen sulfide is in the production of sulfuric acid and elemental sulfur. ... H2S is used to prepare the inorganic sulfides you need to make those products. As a reagent and intermediate, hydrogen sulfide is beneficial because it can prepare other types of reduced sulfur compounds.

7 0
3 years ago
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