Answer:
Disc brake system use a slim rotor and small caliper to halt wheel movement but a drum brake system allow heat to build up inside the drum during heavy braking .
Answer:
Detailed solution is given in attached image
The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.
<h3>What is power?</h3>
Power is the energy transferred per unit time.
Torque is find out by
P = 2πNT/60
10000 = 2π x 2000 x T / 60
T =47.74 N.m
The gear ratio Ne / Ns =4/1
Ns =2000/4 = 500
Ts =Ps x 60/(2π x 500)
Ts =190.96 N.m
Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))
τ max =T/J x D/2
where d₁ = 30mm = 0.03 m
d₀ = 30 +(2x 4) = 38mm =0.038 m
Substitute the values into the equation, we get
τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)
τ max = 28.98 MPa.
Thus, the maximum shear stress in the tube is 28.98 MPa.
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Answer:
current is measured in Ampere (A)
Answer:
Impossible.
Explanation:
The ideal Coefficient of Performance is:
![COP_{i} = \frac{250\,K}{300\,K-250\,K}](https://tex.z-dn.net/?f=COP_%7Bi%7D%20%3D%20%5Cfrac%7B250%5C%2CK%7D%7B300%5C%2CK-250%5C%2CK%7D)
![COP_{i} = 5](https://tex.z-dn.net/?f=COP_%7Bi%7D%20%3D%205)
The real Coefficient of Performance is:
![COP_{r} = \frac{950\,kJ-70\,kJ}{70\,kJ}](https://tex.z-dn.net/?f=COP_%7Br%7D%20%3D%20%5Cfrac%7B950%5C%2CkJ-70%5C%2CkJ%7D%7B70%5C%2CkJ%7D)
![COP_{r} = 12.571](https://tex.z-dn.net/?f=COP_%7Br%7D%20%3D%2012.571)
Which leads to an absurds, since the real Coefficient of Performance must be equal to or lesser than ideal Coefficient of Performance. Then, the cycle is impossible, since it violates the Second Law of Thermodynamics.