Answer:
The pressure exerted by this man on ground
(a) if he stands on both feet is 8.17 KPa
(b) if he stands on one foot is 16.33 KPa
Explanation:
(a)
When the man stand on both feet, the weight of his body is uniformly distributed around the foot imprint of both feet. Thus, total area in this case will be:
Area = A = 2 x 480 cm²
A = 960 cm²
A = 0.096 m²
The force exerted by man on his area will be equal to his weight.
Force = F = Weight
F = mg
F = (80 kg)(9.8 m/s²)
F = 784 N
Now, the pressure exerted by man on ground will be:
Pressure = P = F/A
P = 784 N/0.096 m²
<u>P = 8166.67 Pa = 8.17 KPa</u>
(b)
When the man stand on one foot, the weight of his body is uniformly distributed around the foot imprint of that foot only. Thus, total area in this case will be:
Area = A = 480 cm²
A = 0.048 m²
The force exerted by man on his area will be equal to his weight, in this case, as well.
Force = F = Weight
F = mg
F = (80 kg)(9.8 m/s²)
F = 784 N
Now, the pressure exerted by man on ground will be:
Pressure = P = F/A
P = 784 N/0.048 m²
<u>P = 16333.33 Pa = 16.33 KPa</u>
Answer:
the final temperature is 77.1 °C
Explanation:
Given the data in the question;
Initial temperature; T₁ = 27°C = ( 27 + 273)K = 300 K
Initial absolute pressure P₁ = 300 kPa = ( 300 + 101.325 )kPa = 401.325 kPa
Final absolute pressure P₂ = 367 kPa = ( 367 + 101.325 )kPa = 468.325 kPa
Now, to calculate the final temperature, we use the ideal gas equation;
P₁V/T₁ = P₂V/T₂
but it is mentioned that the rigid tank is closed,
so the volume is the same both before and after.
Change in volume = 0
hence;
P₁/T₁ = P₂/T₂
we substitute
401.325 kPa / 300 K = 468.325 kPa / T₂
T₂ × 401.325 kPa = 300 K × 468.325 kPa
T₂ = [ 300 K × 468.325 kPa ] / 401.325 kPa
T₂ = 140497.5 K / 401.325
T₂ = 350.08 K
T₂ = ( 350.08 - 273 ) °C
T₂ = 77.1 °C
Therefore, the final temperature is 77.1 °C
Answer:Topographic map. Contour line. Learning Objectives. After completing this chapter, you will be able to: □ Define civil engineering and civil drafting.
Explanation:
