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Thepotemich [5.8K]
3 years ago
6

An experimenter finds that standing waves on a string fixed at both ends occur at 24 Hz and 32 Hz , but at no frequencies in bet

ween. Part A What is the fundamental frequency
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

Answer:

8 Hz

Explanation:

Given that

Standing wave at one end is 24 Hz

Standing wave at the other end is 32 Hz.

Then the frequency of the standing wave mode of a string having a length, l, is usually given as

f(m) = m(v/2L), where in this case, m could be 1. 2. 3. 4 etc

Also, another formula is given as

f(m) = m.f(1), where f(1) is the fundamental frequency..

Thus, we could say that

f(m+1) - f(m) = (m + 1).f(1) - m.f(1) = f(1)

And as such,

f(1) = 32 - 24

f(1) = 8 Hz

Then, the fundamental frequency needed is 8 Hz

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Answer:  If one billiard ball hits another, the second will move with the same force as the first.

A child wants to jump to climb a tree (reaction), he must push the ground to propel himself (action).

A man deflates a balloon; the force with which the air comes out causes the balloon to move from one side to the other.

Explanation:

7 0
3 years ago
Read 2 more answers
What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ
borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

\omega = \sqrt{\frac{k}{m}}

now we have

\omega = \sqrt{\frac{k}{1200}}

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

a = \omega^2 A

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

\frac{1}{2}mv^2 = \frac{1}{2}kA^2

here we know that

v = 85 km/h

v = 85 \times\frac{1000}{3600} = 23.61 m/s

now we have

(1200)(23.61^2) = kA^2

A^2 = \frac{6.68 \times 10^5}{k}

now from above equation of acceleration we have

5.0 g = (\frac{k}{m})\sqrt{\frac{6.68 \times 10^5}{k}}

5.0(9.81) = \sqrt{k}(0.68)

k = 5178.8 N/m

6 0
3 years ago
Why is cathode positive in leclanche cell??
laila [671]

Answer:

Because the zinc is reluctant

Explanation:

A leclanche cell contains a conducting solution (electrolyte) of ammonium chloride, a cathode (positive terminal) of carbon, a depolarizer of manganese dioxide (oxidizer), and an anode (negative terminal) of zinc (reductant).

As the Zn2+ ions move away from the anode, leaving their electrons on its surface,

Zn → Zn2+ + 2e−

the anode becomes more negatively charged than the cathode. When the cell is connected to an external electrical circuit, the excess electrons on the zinc anode flow through the circuit to the carbon rod, the movement of electrons forming an electric current.

7 0
3 years ago
Charges q, q, and – q are placed on the x-axis at x = 0, x = 4 m, and x = 6 m, respectively. At which of the following points do
MrRissso [65]

Answer:

can you show a graph but if not i believe the answer is x=6m

Explanation:

7 0
3 years ago
A fairgrounds ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follo
cestrela7 [59]

Answer:

13.37 rev/min

Explanation:

acceleration due to gravity (g) = 9.8 m/s², centripetal acceleration (a_c) = 1.8 * g = 1.8 * 9.8 m/s² = 17.64 m/s².

r = 9 m

Centripetal acceleration (a_c) is given by:

a_c=\frac{v^2}{r} \\\\v=\sqrt{a_c*r} \\\\v=\sqrt{17.64\ m/s^2*9\ m}\\\\v=12.6\ m/s

The velocity (v) is given by:

v = ωr;  where ω is the angular velocity

Hence:

ω = v/r = 12.6 / 9

ω = 1.4 rad/s

ω = 2πN

N = ω/2π = 1.4 / 2π

N = 0.2228 rev/s

N = 13.37 rev/min

4 0
3 years ago
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