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Sladkaya [172]
3 years ago
5

A coil lies flat on a tabletop in a region where the magnetic field vector points straight up. The magnetic field vanishes sudde

nly. When viewed from above, what is the sense of the induced current in this coil as the field fades?
a. The induced current flows counter-clockwise.
b. The induced current flows clockwise.
c. There is no induced current in this coil.
d. The current flows clockwise initially, and then it flows counter-clockwise before stopping.
Physics
1 answer:
Mademuasel [1]3 years ago
6 0

Answer:

Option B - The induced current flows counter-clockwise.

Explanation:

Faraday's law of electromagnetic induction states that whenever a conductor is placed in a changing magnetic field, an electromotive force is induced and that if the conductor circuit is closed, a current is induced which is the induced current. The magnitude of the EMF induced in the coil is therefore proportional to the rate of change of magnetic flux throughout the coil.

Meanwhile, the direction of the induced current is given by Lenz's law which states that the direction of the induced current will oppose the change in electromagnetic force that produced that current.

Since the magnetic field points upwards, the induced current will move in a direction to the left which is counterclockwise

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from the oxidation reaction:

1moles of oxygen requires 4moles of electrons to be discharged at the product

F=96500C/mol

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Mole= 723.6/(4*96500)

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M=0.0018746114

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5 0
3 years ago
Please help on this one?
Sati [7]
I’m pretty sure it’s A
4 0
4 years ago
A particle with charge 3.20×10−19 c is placed on the x axis in a region where the electric potential due to other charges increa
lys-0071 [83]

Answer:

-5 V

Explanation:

The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value

vb−va

is negative.

We can calculate the potential difference between the two points by using the law of conservation of energy:

\Delta K+ \Delta U=0\\\Delta K + q\Delta V=0

where:

\Delta K=+1.6\cdot 10^{-18} J is the change in kinetic energy of the particle

q=3.2\cdot 10^{-19} C is the charge of the particle

\Delta V =V_b-V_a is the potential difference

Re-arranging the equation, we can find the value of the potential difference:

\Delta V=V_b-V_a = -\frac{\Delta K}{q}=-\frac{1.6\cdot 10^{-18} J}{3.2\cdot 10^{-19} C}=-5 V

8 0
3 years ago
A photon ionizes a hydrogen atom from the ground state. The liberated electron 11. recombines with a proton into the first excit
anygoal [31]

Answer:

a) 23.2 e V

b) energy of the original photon is 36.8 eV

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given,

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K combine with photon in first exited state giving out photon of energy

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b) energy of the original photon

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h ν₁  = 23.2 + 13.6

       = 36.8 e V

energy of the original photon is 36.8 eV

3 0
4 years ago
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