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ki77a [65]
3 years ago
10

Any object that has mass and takes up space is considered

Physics
1 answer:
sashaice [31]3 years ago
7 0
Matter. I don't really know how to explain it. Sorry. But anyways, Hope this helps!
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Rubidium forms the positive ion Rb+. Does this ion have more or fewer electrons than the neutral atom?
ohaa [14]

Answer:

The ion has fewer electrons

Explanation:

As Rubidium forms a positive ion Rb⁺ the number of electrons becomes fewer for the atom.

  • A positive charge on an ion indicates that the number of protons for the atom is greater than the number of electrons.
  • This leaves a net positive charge on the atom.
  • For a negatively charged ion, the number of electrons is more than the number of protons because they have gained additional electrons.
  • In a neutral atom, the number of protons and electrons are the same.
7 0
3 years ago
Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the
Fantom [35]

Answer:

The charge on each electrode is

q=0.354 x10^{-12}

Explanation:

The charge to find the equation is development

V=9v

d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )

q=C*V

C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4}  }{0.01}=0.354  \\

q=0.354*9v\\q=3.186x10^{-12} C

3 0
4 years ago
Which type of electromagnetic waves should the scientists' cameras use in order to safely capture images of the sea turtles at n
ad-work [718]

Answer:

D :} if not that is A  that what my thing say where correct

Explanation:

3 0
3 years ago
Read 2 more answers
If a box is labeled 50 lbs, what is it's mass?
aleksandrvk [35]
I would assume it is 50 pounds. that sounds weird?
4 0
4 years ago
A small water droplet in a mist of air is approximated as being a sphere of diameter 1.25 mil. Calculate the terminal velocity a
shtirl [24]

The terminal velocity as it falls through still air is 4.65154 in/s.

The diameter of small water droplet is 1.25 mil= 1.25×0.0254×10^-3 m

                                                                            = 3.175 × 10^-5 m

Now the viscosity of still air is η = 1.83× 10⁻⁵ Pa

 So the formula for drag force is:

                Fd = 6πηrv

  where,  v is the velocity.

Now to attain terminal velocity acceleration must be zero.

            →  W = Fd

                ρVg = 6πrηv

                ρ × 4/3 πr³×g = 6πrηv

                           v = 2/9 × ρgr³/ η

                           v =  2/9 × 10³×9.81×(3.175×10^-3) / 18.6×10^-6

                           v = 0.1181  m/s

                           v = 4.65154 in/s

Learn more about terminal velocity here:

     brainly.com/question/20409472

              #SPJ4

                   

8 0
2 years ago
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