2 years ago

When a particle is moving fast it has a lot of kinetic energy in it. ?

1 answer:

3 0

Answer:

Random particle motion in liquids and gases is a difficult concept for in temperature, the particles move faster as they gain kinetic energy.

Explanation:

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At 25°C, the equilibrium constant Kc for the reaction 2A(aq) ↔ B(aq) + C(aq) is 65. If 2.50 mol of A is added to enough water to

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Answer:

0.146 M

Explanation:

Equation for the reaction :

2A(aq) ↔ B(aq) + C(aq)

$K_c$ = 65

Molar concentration of A = $\frac{2.50 mol}{1.00 L}$

= 2.5 M

2A(aq) ↔ B(aq) + C(aq)

Initial 2.50 0 0

Change - 2x + x + x

Equilibrium 2.50 - 2x +x +x

$K_c =\frac {[B][C]}{[A]^2}$

$65 = \frac{[x][x]}{[2.5-2x]^2}$

$65 = \frac{[x]^2}{[2.5-2x]^2}$

$65 = (\frac{[x]}{[2.5-2x]})^2$

$\sqrt 65 = \sqrt {(\frac{[x]}{[2.5-2x]})^2}$

$8.062 = \frac{x}{2.5-2x}$

8.062(2.5 - 2x) = x

20.155 - 16.124x = x

20.155 = 16.124x+x

20.155 = 17.124x

x = $\frac{20.155}{17.124}$

x = 1.177

[A] = 2.5 - 2x

= 2.5 - 2(1.177)

= 0.146 M

Therefore, the equilibrium concentration of A = 0.146 M

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