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Len [333]
2 years ago
11

Which gas is produced when we add a pinch of baking soda in vinegar​

Chemistry
2 answers:
Luda [366]2 years ago
8 0
When you add a pinch of baking soda into vinegar, carbon dioxide gas is produced
iren [92.7K]2 years ago
7 0

Hey there!

When we add a pinch of baking soda to vinegar we can see the formation/production of <u>carbon </u><u>dioxide</u><u> </u><u>gas </u><u>(</u><u>CO2)</u><u>.</u>

Hope it helps ya!

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Which star is hotter,but less luminous, than polaris
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It would be any white dwarf star
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After severe dust storms in the 1930s, practices were put in place to reduce soil erosion. Which
timurjin [86]

Answer: Farmers were paid to practice soil-conserving techniques like crop rotation and terracing

Explanation:

read about it here: https://www.pbs.org/wgbh/americanexperience/features/dust-bowl-surviving-dust-bowl/

5 0
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The change of matter from a gas state to a liquid state
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5 0
3 years ago
Which one of these is an example of a physical change?
aleksklad [387]
Hey there!

The correct answer to your question is option A.

Sugar dissolving in warm water is an example of a physical change.
This is because sugar dissolving in the water does not create a substance or material. All of the other options are examples of chemical changes, because they eventually become a substance/material.

Hope this helps you.
Have a great day!
6 0
3 years ago
The empirical formula for trichloroisocyanuric acid, the active ingredient in many household bleaches is OCNCI. The molar mass o
TEA [102]

Answer:

These two are equivalent and valid:

       C_3Cl_3N_3O_3

       Cl_3(CN)_3O_3

Explanation:

The molecular superscripts for each atom in the <em>molecular formula</em> are determined by the number of times that the mass of the<em> empirical formula</em> is contained in the<em> molar mass</em>.

<u />

<u>1. Determine the mass of the empirical formula:</u>

OCNCl:

Atomic masses:

  • O: 15.999g/mol
  • C: 12.011g/mol
  • N: 14.007g/mol
  • Cl: 35.453g/mol

Total mass:

  • 15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol

<u />

<u>2. Divide the molar mass by the mass of the empirical formula:</u>

  • 232.41g/mol / 77.470g/mol = 3

<u>3. Multiply each superscript of the empirical formula by the previous quotient: 3</u>

       O_3C_3N__3Cl_3

Or:

       C_3Cl_3N_3O_3

You might also write CN as a group:

          Cl_3(CN)_3O_3

8 0
3 years ago
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