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Len [333]
3 years ago
11

Which gas is produced when we add a pinch of baking soda in vinegar​

Chemistry
2 answers:
Luda [366]3 years ago
8 0
When you add a pinch of baking soda into vinegar, carbon dioxide gas is produced
iren [92.7K]3 years ago
7 0

Hey there!

When we add a pinch of baking soda to vinegar we can see the formation/production of <u>carbon </u><u>dioxide</u><u> </u><u>gas </u><u>(</u><u>CO2)</u><u>.</u>

Hope it helps ya!

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How can you tell one elements from another?
stepladder [879]
The protons in the atom determine what the atom is. It also determines the atomic number<span>. For example, hydrogen has one proton, so it the atomic number is one. Lithium has an atomic number of three because it has three protons.</span>
7 0
3 years ago
Read 2 more answers
Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many mol of CO2 would be produced from the complete
Assoli18 [71]

Answer:

0.208mole of CO2

Explanation:

First, let us calculate the number of mole of HC3H3O2 present.

Molarity of HC3H3O2 = 0.833 mol/L

Volume = 25 mL = 25/100 = 0.25L

Mole =?

Mole = Molarity x Volume

Mole = 0.833 x 0.25

Mole of HC3H3O2 = 0.208mole

Now, we can easily find the number of mole of CO2 produce by doing the following:

NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2

From the equation,

1mole of HC2H3O2 produced 1 mole of CO2.

Therefore, 0.208mole of HC2H3O2 will also produce 0.208mole of CO2

6 0
3 years ago
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How many moles of O2 is needed to form 2.19 moles of CO2 in the reaction
bagirrra123 [75]
It is always half of what the o2 is
6 0
3 years ago
What volume is occupied by 3.760 g of oxygen gas at a pressure of 88.4
Lorico [155]

Answer:

3.2 L

Explanation:

Given data:

Mass of oxygen = 3.760 g

Pressure of gas = 88.4 Kpa (88.4×1000 = 88400 Nm⁻²)

Temperature = 19°C (19+273.15 = 292.15 K)

R = 8.314 Nm K⁻¹ mol⁻¹

Volume occupied = ?

Solution:

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 3.760 g/ 32 g/mol

Number of moles = 0.12 mol

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant

T = temperature in kelvin

V = nRT/P

V = 0.12 mol ×  8.314 Nm K⁻¹ mol⁻¹ × 292.15 K /88400 Nm⁻²

V = 291.472 Nm /88400 Nm⁻²

V = 0.0032 m³

m³ to L:

V = 0.0032×1000 = 3.2 L

4 0
3 years ago
Problem: Convert 30 cm to mm.<br> Need full process pls help
marta [7]

Answer: 300mm

Explanation:

30cm x (10mm/1cm) x <em>(1mm/1mm)</em> = 300mm

<em>Btw, I'm not sure about the </em><u><em>(1mm/1mm).</em></u>

3 0
3 years ago
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