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3 years ago

Describe the three main sub?atomic particles. Include mass (with units), charge and location for each.

1 answer:

5 0

Electron - negligible mass, negative charge, orbits the nucleus
Proton - 1 AMU, positive charge, in the nucleus
Neutron, 1 AMU, no charge, in the nucleus

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Please help with this question

Anastasy [175]

Answer:

215 amu

Explanation:

In the reactants:

There is 1 iron atom, 3 chlorine atoms, 6 hydrogen atoms and 3 oxygen atoms:

Fe: 56 × 1 = 56
Cl: 35 × 3 = 105
H: 1 × 6 = 6
O: 16 × 3 = 48

56 + 105 + 6 + 48 = 215 amu

Hope this helps!

8 0

2 years ago

What is the mass of 4.2 x 10^24 molecules of Ca(OH)2

kvv77 [185]

Udirirororofofkflfofofofo

6 0

3 years ago

Read 2 more answers

If 24k gold is the highest purity (100%), then a 6 Karat piece of gold jewelry would contain what percentage of gold?

krok68 [10]

Answer:

25% gold.

Explanation:

6 is 25 percent of 24, so 6 karat gold would be 25% gold.

4 0

3 years ago

A large clump of ice is placed into a saucepan and heated to at least 1000C. Explain the changes that would take place by using

Mamont248 [21]

By start heating the water so,
1- the physical changes to the water will begin by going through different states of matter such as solid, liquid and gas vapor.

2- Water is a compound, not an element (H2o).

3- It will change according to the temperature change also:

a- At zero C° it is at a freezing temperature.

b- when it starts to be heated from 0C° to 100 c°, it starts to change from freezing to the liquid state.

c- At 100C° the water starts to change from liquid to vapor state until it disappears.

7 0

3 years ago

Read 2 more answers

You are given a solid that is a mixture of Na2SO4 and K2SO4. A 0.205-g sample of the mixture is dissolved in water. An excess of

Svetach [21]

Answer:

Mass of SO₄⁻² = 0.123 g.

Mass percentage of SO₄⁻² = 41.2%

Mass of Na₂SO₄ = 0.0773 g

Mass of K₂SO₄ = 0.1277 g

Explanation:

Here we have

We place Na₂SO₄ = X and

K₂SO₄ = Y

Therefore

X +Y = 0.205 .........(1)

Therefore since the BaSO₄ is formed from BaCl₂, Na₂SO₄ and K₂SO₄ we have

Amount of BaSO₄ from Na₂SO₄ is therefore;

$X\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, Na_2SO_4}$

Amount of BaSO₄ from K₂SO₄ is;

$Y\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, K_2SO_4}$

Molar mass of

BaSO₄ = 233.38 g/mol

Na₂SO₄ = 142.04 g/mol

K₂SO₄ = 174.259 g/mol

$X\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, Na_2SO_4}$ = $X\times\frac{233.38 }{142.04}$ = 1.643·X

$Y\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, K_2SO_4}$ = $Y\times\frac{233.38 }{174.259 }$ = 1.339·Y

Therefore, we have

1.643·X + 1.339·Y = 0.298 g.....(2)

Solving equations (1) and (2) gives

The mass of SO₄⁻² in the sample is given by

Mass of sample = 0.298

Molar mass of BaSO₄ = 233.38 g/mol

Mass of Ba = 137.327 g/mol

∴ Mass of SO₄ = 233.38 g - 137.327 g = 96.05 g

Mass fraction of SO₄⁻² in BaSO₄ = 96.05 g/233.38 g = 0.412

Mass of SO₄⁻² in the sample is 0.412×0.298 = 0.123 g.

Percentage mass of SO₄⁻² = 41.2%

Solving equations (1) and (2) gives

X = 0.0773 g and Y = 0.1277 g.

8 0

3 years ago