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inna [77]
4 years ago
11

A+B=37 A-B=9 Dau coroana

Mathematics
1 answer:
azamat4 years ago
4 0
12-3=9
30+7=37
I believe you just plug in any two numbers that will come out to 9 when subtracted or 37 when added.
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As part of a statistics project, a teacher brings a bag of marbles containing 600 white marbles and 300 red marbles. She asks he
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E. The 31 red marbles drawn by the student
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4 years ago
If you were asked to convert 75 m/s to km/hr, which conversation factors would you need to use. Select all that apply.
Vilka [71]

Answer:

You need to use A, B, and C.

Step-by-step explanation:

Let's treat the units as variables. I'll illustrate why in a moment.

75 m/s =\frac{75m}{1s} \\\\\frac{75m}{1s}*\frac{1km}{1000m}=\frac{75m*km}{1000m*s}\\\\\frac{75m*km}{1000m*s}*\frac{60s}{1min}=\frac{(75*60)m*km*s}{1000m*s*min}\\\\\frac{4500m*km*s}{1000m*s*min}*\frac{60min}{1h}=\frac{4500m*km*s*min}{1000m*s*min*h}

Now, as you can see, we have a giant mess of units to deal with. This is where we can treat the units like separate variables and use a bit of algebra to make our lives easier:

\frac{4500m*km*s*min}{1000m*s*min*h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}\\\\\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}\\\\\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}\\\\\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}=\frac{4500}{1000}*\frac{km}{h}\\

\frac{4500}{1000}*\frac{km}{h}=\frac{45}{1}*\frac{km}{h}=45 \frac{km}{h}

So, backtracking through that entire mess, we had to use \frac{1km}{1000m} ,\frac{60s}{1min} ,\frac{60min}{1h}.

These correspond to the options of A, C, and B accordingly.

So you need to use A, B, and C.

8 0
3 years ago
Which equation justifies why seven to the one third power equals the cube root of seven?
Rudiy27

The equation that  justifies why seven to the one third power equals the cube root of seven is seven to the one third power all raised to the third power equals seven to the one third times three power equals seven

<h3>How to solve an equation?</h3>

using indices law,

\sqrt[n]{x}  = x^{1 / n}

Therefore, let's justify

7^{1/3}  = \sqrt[3]{7}

Hence, the justification is as follows;

(7^{1 /3}) ^{3} =(7^{1/3})^{3}  = 7

Therefore, the justification of is that seven to the one third power all raised to the third power equals seven to the one third times three power equals seven

learn more on equation here: brainly.com/question/13426221

#SPJ1

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On a number line 7.29 and -7.29 are the same point. true or false
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Answer should be False
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ANSWER ASAP GIVING BRAINLIEST AND STUFF!
never [62]

Answer:

You could make an organized list, sample space, table, or tree diagram.

4 0
3 years ago
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