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WITCHER [35]
3 years ago
8

The equilibrium constants for the chemical reaction N 2(g) + O 2(g) 2NO(g) are K P = 1.1 × 10 –3 and 3.6 × 10 –3 at 2,200 K and

2,500 K, respectively. Which one of these statements is true?
Chemistry
1 answer:
sattari [20]3 years ago
7 0

Answer:

The answer is "At 2200K, NO(g)'s partial pressure is below 2500K. C.KP by a factor of (RT) is lower than Kc"

Explanation:

In the given question choices were missing so, the correct choice can be defined as follows:

Given:

Reaction equation: \bold{N_2(g) + O_2(g) \longrightarrow 2NO(g)}

when temperature 2,200 K the value of KP = 1.1 \times 10^{-3}

when temperature 2,500 K the value of KP = 3.6 \times 10^{-3}

value of kp=?

KP= \frac{(PNO)^2}{(PN_2)(PO_2)}

In the above formula the value of (PN_2) and (PO_2) is defined in the denominator section and the value of (PNO) is defined in the numerator section that defines the value of KP is increases.so, the temperature of the KP will be KP ∝ (PNO).

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Suppose an ice cube weighing 36.0 g at a temperature of 10°C is placed in 360 g water at a temperature of 20°C. Calculate the te
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10.44 °C

Explanation:

When the thermal equilibrium is reached, both of the substances have the same final temperature (T). The liquid water will lose heat, and the ice cube will absorb this heat. The temperature of the ice will increase until it reaches 0°C, at this temperature, it will change of phase for liquid, absorbing heat, but without a change in the temperature. Then the temperature will increase until the equilibrium.

By the energy conservation, the total amount of heat must be equal to 0:

Qice + Qmelting + Qliquid1 + Qliquid2 = 0

Liquid 1 is the ice after melting, and liquid 2 the liquid that was already at the flask. When there's a change of temperature:

Q = n*c*ΔT, where n is the number of moles, c is the heat capacity and ΔT is the temperature change (final - initial). The temperature variation in °C is equal in K, so the temperature may be used in °C.

The melting heat is:

Q = n*Hfus, Hfus = 6007 J/mol

The molar mass of the water is 18 g/mol, so the number of moles of the water and the ice are:

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Qice + Qmelting + Qliquid1 + Qliquid2 = 0

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760 + 12014 + 150T + 1500T - 30000 = 0

1650T = 17226

T = 10.44 °C

4 0
3 years ago
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