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4 years ago

Which one is rong Scenario Equation Graph or Table

Mathematics

2 answers:

Kay [80]4 years ago

7 0

The scenario is wrong. according to the three other tools, the hot air balloon would be increasing in altitude, not descending.

melisa1 [442]4 years ago

6 0

Scenario is incorrect

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Nina [5.8K]

Answer:

6cm is 4x by 1 Ilan?? Di mo Alam no

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3 years ago

What is one of the solutions to the following systems of equations? Y squared plus X squared equals 65 and Y plus X equals seven

alukav5142 [94]

Answer:

Step-by-step explanation:

y^2 + x^2 = 65

y + x = 7......x = 7 - y

y^2 + (7 - y)^2 = 65

y^2 + (7 - y)(7 - y) = 65

y^2 + 49 - 7y - 7y + y^2 = 65

2y^2 - 14y + 49 = 65

2y^2 - 14y + 49 - 65 = 0

2y^2 - 14y - 16 = 0

2(y^2 - 7y - 8) = 0

2(y + 1)(y - 8) = 0

y + 1 = 0 y - 8 = 0

y = -1 y = 8

solution :

y = -1...........y + x = 7.....-1 + x = 7......x = 7 + 1......x = 8........(8,-1)

y = 8........y + x = 7.....8 + x = 7......x = 7 - 8........x = -1........(-1,8)

7 0

3 years ago

The tables represent two linear functions in a system.

lisov135 [29]

First table
y = -4x +10
if x = 8, y = -4(8) + 10 = -22

second table
y =-3x + 2
if x = 8, y = -3(8) + 2 = -22

answer

D (8, –22) <span>is the solution to this system</span>

6 0

3 years ago

Read 2 more answers

What is the ratio of 45 to 35

Mademuasel [1]

8 0

3 years ago

Read 2 more answers

In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean

Nastasia [14]

Answer:

a) $\bar X =\frac{46+54}{2}=50$

And the margin of error is given by:

$ME= \frac{54-46}{2}= 4$

The confidence level is 0.96 and the significance level is $\alpha=1-0.96=0.04$ and the value of $\alpha/2 =0.02$ and the margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

We can calculate the critical value and we got:

$z_{\alpha/2} = 2.05$

And if we solve for the deviation like this:

$\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}$

And replacing we got:

$\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45$

b) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828$

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor $\sqrt{2}$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma$ represent the population standard deviation

n=80 represent the sample size

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case we can calculate the mean like this:

$\bar X =\frac{46+54}{2}=50$

And the margin of error is given by:

$ME= \frac{54-46}{2}= 4$

The confidence level is 0.96 and the significance level is $\alpha=1-0.96=0.04$ and the value of $\alpha/2 =0.02$ and the margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

We can calculate the critical value and we got:

$z_{\alpha/2} = 2.05$

And if we solve for the deviation like this:

$\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}$

And replacing we got:

$\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45$

Part b

For this case is the sample size is doubled the margin of error would be:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828$

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor $\sqrt{2}$

5 0

3 years ago