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stepladder [879]
3 years ago
8

What type of bond would you expect in a compound of oxygen & sodium?

Chemistry
1 answer:
Aleks04 [339]3 years ago
5 0
4Na+O2--›2Na2O
Ionic bond
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∆H° rxn = - 93 kJ

Explanation:

Recall that a change in standard in enthalpy, ∆H°, can be calculated from the inventory of the energies, H, of the bonds  broken minus bonds formed (H according to Hess Law.

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∆H° rxn = ∑  H bonds broken  - ∑ H bonds formed

∆H° rxn = [ 1(945 kJ)   + 3 (432 kJ) ] - [ 6 (389 k J]

∆H° rxn = 2,241 kJ -2334 kJ = -93 kJ

be careful when reading values from the reference table since you will find listed N-N bond energy (single bond), but we have instead a triple bond,  N≡N,  we have to use this one .

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We count the amount of each element on each side, and the products should have the same number as the reactants.

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