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2 years ago

Answer please help me

Physics

1 answer:

aksik [14]2 years ago

7 0

Answer:

It is showing the wavelength.

Explanation: Hope it helps you:)))

have a good day

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A merry-go-round on a playground consists of a horizontal solid disk with a weight of 805 N and a radius of 1.47 m. A child appl

snow_tiger [21]

Answer:

255.34 J

Explanation:

Given,

Weight of disk = 805 N

radius = 1.47 m

Force applied by the child = 49 N

time = 2.95 s

KE = ?

mass of the disk

$M = \dfrac{W}{g}= \dfrac{805}{9.81} = 82.059\ Kg$

Moment of inertia of the disk

$I = \dfrac{1}{2}Mr^2$

$I = \dfrac{1}{2}\times 82.059\times 1.47^2 =88.66\ kgm^2$

Torque on the child

$\tau = F \times r = 49 \times 1.47 = 72.03 Nm$

Angular acceleration

$\alpha = \dfrac{\tau}{I}=\dfrac{72.03}{88.66} = 0.812\ rad/s^2$

So, angular speed at t = 2.95 s

$\omega = \alpha t = 0.812 \times 2.95 = 2.4\ rad/s$

Now, KE of the merry go round

$KE = \dfrac{1}{2} I \omega^2 = \dfrac{1}{2}\times 88.66\times 2.4^2 = 255.34 J$

Hence, the Kinetic energy of the merry go round = 255.34 J

8 0

3 years ago

4. A graduated cylinder is used to measure a. volume b. weight d. inertia c. mass

cestrela7 [59]

The Answer is A. Volume

6 0

3 years ago

Can you help me answer this?

Pavel [41]

The answer is D. If you aren't consistent with your drop positions, then your data may be invalid. To be frank: it basically screws over the experiment.

5 0

4 years ago

If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu

zubka84 [21]

Answer:

minimum speed is 15.35 m/s

frictional coefficient is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² = 236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 = 0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245 = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient is 0.26

4 0

3 years ago

Read 2 more answers

Which type of circuit is shown?

ivann1987 [24]

Answer:

I think it's D. open series circuit .

Explanation:

hope it helps you!

7 0

4 years ago

Answer please help me ​

Answer please help me