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Elena L [17]
3 years ago
11

What are the reactants and products of fermentation?

Chemistry
1 answer:
SVEN [57.7K]3 years ago
8 0
The fermentation reaction is a biochemical reaction which involves a microorganism consuming a substrate (Carbon -source) and in order to produce several products such as alcohol, proteins, amino acids, biogas etc.

The most common reactant/substrate for a fermentation reaction is sugar, specifically glucose and the most common product is alcohol. If the fermentation process is aerobic in nature, then a oxygen is also required as reactant. By products include carbon dioxide, sulfur oxides etc. 

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How do I round 10.25 to only 3 significant digits
Lady_Fox [76]
10.3 is good the correct rounding of three sig figures

3 0
3 years ago
A photon of light possesses 5 x 10^-19 J of energy. Calculate its frequency
saveliy_v [14]

Answer:

The frequency of photon is 0.75×10¹⁵ s⁻¹.

Explanation:

Given data:

Energy of photon = 5×10⁻¹⁹ J

Frequency of photon = ?

Solution:

Formula;

E = hf

h = planck's constant = 6.63×10⁻³⁴ Js

5×10⁻¹⁹ J =  6.63×10⁻³⁴ Js ×f

f =  5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js

f = 0.75×10¹⁵ s⁻¹

The frequency of photon is 0.75×10¹⁵ s⁻¹.

4 0
2 years ago
4. What type of evidence do you think would be most difficult to collect
mars1129 [50]

I think it is trace evidence since it is really small and hard to find.

3 0
3 years ago
Read 2 more answers
Calculate the molality of a solution that contains 51.2 g of naphthalene, C10H8, in 500 mL of carbon tetrachloride. The density
PtichkaEL [24]

<u>Answer:</u> The molality of naphthalene solution is 0.499 m

<u>Explanation:</u>

Density is defined as the ratio of mass and volume of a substance.

\text{Density}=\frac{\text{Mass}}{\text{Volume}} ......(1)

Given values:

Volume of carbon tetrachloride = 500 mL

Density of carbon tetrachloride = 1.60 g/mL

Putting values in equation 1, we get:

\text{Mass of carbon tetrachloride}=(1.60g/mL\times 500mL)=800g

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molarity:

\text{Molality of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent (in g)}} .....(2)

Given values:

Given mass of naphthalene = 51.2 g

Molar mass of naphthalene = 128.17 g/mol

Mass of solvent = 800 g

Putting values in equation 2, we get:

\text{Molality of naphthalene}=\frac{51.2\times 1000}{128.17\times 800}\\\\\text{Molality of naphthalene}=0.499m

Hence, the molality of naphthalene solution is 0.499 m

4 0
2 years ago
HI decomposes to H2 and I2 by the following equation: 2HI(g) → H2(g) + I2(g);Kc = 1.6 × 10−3 at 25∘C If 1.0 M HI is placed into
dsp73

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.037 M

<u>Explanation:</u>

We are given:

Initial concentration of HI = 1.0 M

The given chemical equation follows:

                       2HI(g)\rightleftharpoons H_2(g)+I_2(g)

<u>Initial:</u>               1.0

<u>At eqllm:</u>        1.0-2x          x           x

The expression of K_c for above equation follows:

K_c=\frac{[H_2][I_2]}{[HI]^2}

We are given:

Kc=1.6\times 10^{-3}

Putting values in above expression, we get:

1.6\times 10^{-3}=\frac{x\times x}{(1.0-2x)^2}\\\\x=-0.043,0.037

Neglecting the negative value of 'x' because concentration cannot be negative

So, equilibrium concentration of hydrogen gas = x = 0.037 M

Hence, the concentration of hydrogen gas at equilibrium is 0.037 M

6 0
2 years ago
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