Question

What magnitude charge creates a 1.70 N/C electric field at a point 4.60 m away? Express your answer with the appropriate units.

Answer 1

Answer:

$Q=4.0*10^{-9}C$

Explanation:

Electric field of a charge:

$E=k*\frac{Q}{R^{2}}$

$Q=\frac{E*R^{2}}{K}=1.7*4.6^{2}/(9*10^{9})=4.0*10^{-9}C$