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4 years ago

Why earth have gravity?

1 answer:

4 0

On earth there is a force within the planet. This force creates a sort of magnet to keep the planet's being and thing on it together. This force also has a role in the solar system as it helps it move.

The source: https://spaceplace.nasa.gov/what-is-gravity/en/

Hope i helped

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If the western component of the wind is half of the south, what is the angle of the wind with the south?

den301095 [7]

Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

$\tan(x) = \frac{opp}{adj}$

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

$\tan(x) = \frac{ - \frac{a}{2} }{ - a}$

$\tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2}$

Now we take the arctan or inverse tan of 1/2.

$\tan {}^{ - 1} ( \frac{1}{2} ) = 26.57$

3 0

2 years ago

Read 2 more answers

HELP!

julia-pushkina [17]

Answer:

too little body fat is a health risk

Explanation:

IF you do not have enough body fat you can have bad things happen to you

6 0

3 years ago

A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)

katen-ka-za [31]

Answer:

Velocity will be equal to 7.31 m/sec

Explanation:

We have given mass of the student m = 61 kg

Height of the water slide h = 12.3 m

Acceleration due to gravity $g=9.8m/sec^2$

Potential energy is equal to $U=mgh=61\times 9.8\times 12.3=7352.94J$

Work done due to friction = -5800 J

So energy remained = 7352.94-5800 = 1552.94 J

This energy will be equal to kinetic energy

So $\frac{1}{2}mv^2=1552.94$

$\frac{1}{2}\times 61\times v^2=1552.94$

$v^2=50.91$

v = 7.13 m/sec

7 0

3 years ago

The length of a certain wire is kept same while its radius is doubled. what is the change in the resistance of this wire?

kaheart [24]

The resistance of a wire is given by
$R= \frac{\rho L}{A}$
where $\rho$ is the resistivity of the material, L the length of the wire and A its cross-sectional area.

In the problem, $\rho$ and L remain the same, while A changes because the radius changes. The area is given by:
$A=\pi r^2$
This means that if we double the radius (2r), the area becomes
$A_{new}= \pi (2r)^2 = 4 \pi r^2 =4A$
And therefore, the new value of the resistance is
$R_{new} = \frac{\rho L}{4 A}= \frac{1}{4}R$

So, when the radius is doubled, the resistance becomes $\frac{1}{4}$ of its original value.

6 0

4 years ago

why did scientists using classical, newtonian physics have difficulty explaining the photoelectric effect

zzz [600]

The correct answer is :

According to classical electrodynamics, light energy is a wave that is absorbed by atoms in a manner similar to how an object absorbs radiant heat. So, the atoms of a metal would absorb more energy the brighter the light was. It would be feasible for an electron in a metal to break free from its atoms if it received enough energy from the incoming wave. The more energy absorbed, the more energetic the metal's released electrons would be. Additionally, no electrons could conceivably be ejected until each atom had enough light energy. Light intensity was far more important than light frequency.

In many respects, the photo-electric effect contradicted this strategy:

If the light was below a specific frequency, no matter how bright it was, no electrons were released. Increased light intensity increased the number of electrons that were released, but not their energy, if the light was above this frequency.
Regardless of how weak the light was, electrons were nearly immediately emitted from the metal.
Even though the intensity of the light was reduced, an increase in its frequency led to more energising electrons leaving the metal.

To learn more about photo-electric effect refer the link:

brainly.com/question/25630303

#SPJ4

7 0

1 year ago