The average velocity or displacement of a particle for the first time interval is <u>Δs / Δt = 6 cm/s.</u>
Solution:
As we know that displacement is calculated in centimeters and the unit of time is second.
The average velocity for the first interval [1,2] is given
Δs / Δt = s (t2) - s (t) / t2 - t1
Δs / Δt = 2sin2 π + 3cos 2 π - ( 2sin π + 3cos π ) / 2 - 1
Δs / Δt = 2(0) + 3(1) - 2(0) - 3 (-1) / 1
Δs / Δt = 6 cm/s
Thus the average velocity or displacement of a particle for the first time interval is Δs / Δt = 6 cm/s
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The complete question is:
The displacement of a particle moving back and forth along a line is given by the following equation s(t) = 2sin π t + 3cos π t. Estimate the instantaneous velocity of the particle when t = 1
The Three fission reactions will produce nine neutrons
<h3>Meaning of Fission</h3>
Fission can be defined as a nuclear process that involves the breaking of a whole nuclear matter into smaller bits.
In a fission reaction, the matter is broken down into simpler bits.
In conclusion, The Three fission reactions will produce nine neutrons
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Answer:
Explanation:
Option a is correct
If puck and pick constitute a system then the momentum of the system is conserved but not this may not be valid for the puck .
Option e is correct
If puck and pick is the system then momentum is conserved but because of the presence of friction, mechanical energy is not conserved.
Friction will cause the energy to dissipate in heat.
Answer:
Tangential speed=5.4 m/s
Radial acceleration=
Explanation:
We are given that
Angular speed=2.59 rev/s
We know that
1 revolution=
2.59 rev=
By using 
Angular velocity=
Distance from axis=r=0.329 m
Tangential speed=
Radial acceleration=
Radial acceleration=
The distance between Mars and the Sun in the scale model would be 1140 m
Explanation:
In this scale model, we have:
represents an actual distance of

The actual distance between Mars and the Sun is 228 million km, therefore

On the scale model, this would corresponds to a distance of
.
Therefore, we can write the following proportion:

And solving for
, we find:

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