A bird flies 200 km in 4.5 hours. What is the birds average speed?

1. Write down the readings on the side of Figs. 6 (a), (b) and (c) respectively. What is the least count of instrument scale for

alexandr402 [8]

Explanation:

This should be right. if any doubt post a comment.

3 0

2 years ago

Consider a string of total length L, made up of three segments of equal length. The mass per unit length of the first segment is

zzz [600]

Answer:

Explanation:

Length of each segment is $\frac{L}{3}$

Speed of wave in first segment is $v_1=\sqrt{\frac{T_s}{\mu}}$

Speed of wave in second segment is $v_2=\sqrt{\frac{T_s}{2\mu}}$

Speed of wave in third segment is $v_3=\sqrt{\frac{T_s}{\frac{\mu}{4}}}=\sqrt{\frac{4T_s}{\mu}}$

Now time for the transverse wave to propagate is

$t=t_1 + t_2 + t_3\\=\frac{(\frac{L}{3})}{v_1}+\frac{(\frac{L}{3})}{v_2} + \frac{(\frac{L}{3})}{v_3}\\\\=(\frac{L}{3})(\frac{1}{\sqrt{\frac{T_s}{\mu}}} + \frac{1}{\sqrt{\frac{T_s}{2\mu}}} + \frac{1}{\sqrt{\frac{4T_s}{\mu}}})$

simplifying we get

$t=(\frac{3+2\sqrt{2}}{6})L\sqrt{\frac{\mu}{T_s}}$

3 0

3 years ago

How are pendulums used in society? Give an example of a real-world pendulum that transfers a lot of energy.

mart [117]

Answer:

An old clock that has a swinging pendulum

Explanation:

7 0

4 years ago

A spring is hanging from the ceiling. When a 250 gram of mass is attached to the free end, the spring elongates by 5 cm. The spr

lord [1]

Answer:

k = 49 N/m

Explanation:

Given that,

Mass, m = 250 g = 0.25 kg

When the mass is attached to the end of the spring, it elongates 5 cm or 0.05 m. We need to find the spring constant. Let it is k.

The force due to mass is balanced by its weight as follows :

mg=kx

$k=\dfrac{mg}{x}\\\\k=\dfrac{0.25\times 9.8}{0.05}\\\\k=49\ N/m$

So, the spring constant of the spring is 49 N/m.

8 0

3 years ago

A 0.050 kg toy truck moving right at 0.20 m/s collided with a toy car weighing 0.015 kg initially at rest, on a frictionless tra

Kamila [148]

Answer:

0.1667 m/s

Explanation:

m1V1 + m2V2 = m1V3 + m2V4

0.01 = ( 0.0075) + (0.015 * V4)

V4 = (0.01 - 0.0075) / (0.015)

V4= 0.1667

7 0

3 years ago

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