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romanna [79]
3 years ago
5

Which is an example of pure chemistry

Chemistry
1 answer:
Alexeev081 [22]3 years ago
5 0

Examples of pure substances include tin, sulfur, diamond, water, pure sugar, table salt and baking soda. Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances which are chemical elements. All elements are pure substances.

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What are ionic compounds ​
musickatia [10]
Ionic compound is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding
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3 years ago
What is the empirical formula for P4O10?
Sphinxa [80]

Answer: P2O5

Explanation: You divide both subscripts by 2 to get the empirical formula.

8 0
3 years ago
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Suppose an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron. Comple
AfilCa [17]

Explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is ^{4}_{2}\alpha. Whereas a neutron is represented by a symbol ^{1}_{0}n, that is, it has zero protons and only 1 neutron.

Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

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5 0
3 years ago
Calculate the molarity of 13.1 g of NaCl in 727 mL of solution
valentina_108 [34]

Answer:

The molarity of the solution is 0,31 M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

13,1 g ---------x= (13,1 g x 1 mol NaCl)/58, 5 g= 0, 224 mol NaCl

727 ml solution------ 0, 224 mol NaCl

1000ml solution------x= (1000ml solutionx0, 224 mol NaCl)/727 ml solution

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5 0
3 years ago
Determine the total number of atoms contain in a 2.00 moles of Ni
spayn [35]

Answer:

2.00 moles of Ni has 1.2 *10^24 atoms

Explanation:

Step 1: Data given

Number of moles Ni = 2.00 moles

Number of Avogadro = 6.022*10^23 /mol

Step 2: Calculate number of atoms

Number of particles (=atoms) = Number of Avogadro *  number of moles

Number of atoms = 6.022 * 10^23 /mol * 2.00 moles

Number of atoms = 1.2*10^24 atoms

2.00 moles of Ni has 1.2 *10^24 atoms

4 0
3 years ago
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