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nevsk [136]
3 years ago
14

Source water pollution in Madagascar

Engineering
1 answer:
vodka [1.7K]3 years ago
7 0

Answer:

What is the question?

Explanation:

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Technician A says automotive gasoline engines run on the 2 stroke principal. Technician B says Diesel engine hace less compressi
d1i1m1o1n [39]

Answer:

both are incorect

Explanation:

2 stroke principal is a mix of gasoline and engine oil a normal gasoline engine does not run on 2 stroke fuel

technician B is also wrong Diesel engines generally generate much higher compersion than gasoline engines

3 0
2 years ago
Which of the following would require the filing of an EIS? a. expansion of an airport in a national park b. allowing snowmobiles
alekssr [168]

Answer:

d. All of the above would require an EIS.

Explanation:

A document prepared with the aim of describing the impacts of suggested operations on the environment is an Environmental Impact Statement (EIS). There was a mistake. An Environmental Impact Statement (EIS) is therefore a report describing the environmental effects resulting from a current action. All of the activities above would have an effect on the environment and therefore must fill an EIS

6 0
3 years ago
Program MS. Word digunakan sebagai
Anika [276]

Answer:

EnGliSh?

Explanation:

5 0
3 years ago
Injection melding is a process that
Bumek [7]

Answer:

mark brainliest :)

Explanation:

Injection Molding. Injection molding is the most commonly used manufacturing process for the fabrication of plastic parts. ... The plastic is melted in the injection molding machine and then injected into the mold, where it cools and solidifies into the final part.

Materials: Thermoplastics

5 0
3 years ago
A damped harmonic oscillator consists of a mass on a spring, with a damping force proportional to the speed of the block. If the
Murrr4er [49]

Answer:

TOTAL ENERGY = 0.74 j

Explanation:

Given data:

spring constant is 350 N/m

m = 0.24 kg

b = 0.41 kg/s

A = 0.075 M

\omega = \sqrt{\frac{k}{m}}

             = \sqrt{\frac{350}{0.24}}

y = e^{\frac{-b}{2m} t} A cos(\omega t)

  =e^{\frac{-0.41}{2*0.24} t} cos (\sqrt{\frac{350}{0.24}} t) *0.075

after one full cycle, mass will be at extreme point, hence K,E = 0

But total energy remain same

y after one full cycle is\

y =e^{\frac{-0.41}{2*0.24} 2\pi \sqrt{\frac{0.24}{350}}} cos (2\pi*0.075)

y = 0.06517 m

y = 6.517 cm

total energy = \frac{1}{2} k y^2

= \frac{1}{2}* 350* 0.06517^2 = 0.742 J

8 0
3 years ago
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