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2 years ago

What is voltage drop?

Engineering

1 answer:

lord [1]2 years ago

6 0

Answer:

Explanation:

It is the voltage a voltmeter would read when connected across something that has resistance.

___________0_________O______O_______

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|_____________________| |_____________ |

The diagram above is supposed to represent 3 lightbulbs connected in series. The vertical lines in the middle are supposed to be a battery which powers the three light bulbs. If you put a voltmeter across one of the lightbulbs, it will read a voltage that is 1/3 of the voltage of the battery.

Answer

That reading you get across the one light bulb is The Voltage Drop.

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5)The temperature of the blade is 800°C.

6)The formula for the creep rate in the steady-state regime is dε /dt = 1 x 10-5 σ4 exp (-2 eV/kT)

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$\frac{\delta \epsilon}{\delta t} = (1 \times {10}^{-5})\sigma^4 exp^(\frac{-2eV}{kT} )$

$\frac{\epsilon_{initial} - \epsilon _{primary}}{t_{initial}-t_{final}} = 1 \times 10^{-5}(100)^{4}exp(\frac{-2eV}{8.62\times10^{-5}(\frac{eV}{K} )(800+273)K} )$

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$\epsilon_{initial} - \epsilon _{primary}} = 0.002 - 0.003 = -0.001$

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solving the above equation,

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Tfinal = 2459.82 hr

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