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Phoenix [80]
4 years ago
14

Your pet hamster sits on a record player whose angular speed is constant. If he moves to a point twice as far from the center, t

hen his linear speed
doubles

halves

remains the same
Physics
1 answer:
baherus [9]4 years ago
6 0

Answer:

doubles

Explanation:

The relationship between angular speed and linear speed in case of a circular motion is the following:

v=\omega r

where

v is the linear speed

\omega is the angular speed

r is the distance from the centre of the circular path

In this proble, the pet hamster moves to a point twice as far from the center; this means that its distance from the centre, r', is doubled:

r'=2r

While the angular speed \omega remains the same. Therefore, the new linear speed is

v'=\omega r' = \omega (2r)=2 \omega r=2v

So, the correct answer is

the linear speed doubles

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An automobile traveling along a straight road increases its speed from 30.0 m/s to 50.0 m/s in a distance of 180 m. If the accel
inessss [21]

Answer:

4.5sec

Explanation:

From the question above, the following are the parameters that are given

u= 30m/s

v= 50m/s

s= 180m

First of all we have to find the acceleration by using the third equation of motion

V^2= U^2 + 2as

50^2= 30^2 + 2(a)(180)

2500= 900 + 360a

Collect the like terms

2500-900= 360a

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Divide both sides by the coefficient of a which is 360

1600/360=360a/360

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The next step is to find the time. To do this we will have to use the first equation of motion

v= u + at

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